2-Neutron Correlation

Big Detector Solid Angle Calculations

MCNPX Simulation

• 14 MeV neutron source, emitted isotropically ($4\pi$)
  
• Detector placed 1m away from source
  
  • face of the detector is 15.24cm x 76.2cm, and 3.6cm deep
    

The solid angle can be found from the number of particles hitting the detector as:
$\Delta \Omega = 4\pi*\frac{hits}{hits + misses}$

Results

1E9 Neutrons generated

• 8618287 neutrons hit the detector
• $\Delta \Omega = 0.108 Sr$

As a test to verify our results

We change the detector size to 1cm by 1cm and used 1E9 neutrons again

• 32061 neutrons struck the detector
• $\Delta \Omega = 0.0004 Sr$

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