Neutron energy resolution in NaI detector
[math]\displaystyle{ E_n = \frac{m}{2}\left( \frac{d}{t_n} \right)^2 }[/math]
[math]\displaystyle{ \delta E_n = -\frac{2 \sqrt{2}}{\sqrt{m} d}\ E_n^{3/2} \delta t_n }[/math]
- [math]\displaystyle{ \delta t_n = 15\ ns }[/math]
- [math]\displaystyle{ mc^2 = 938\ MeV }[/math]
[math]\displaystyle{ d = 0.5\ m: \ \ \ ( \delta E_n/E_n ) = 0.83\ E_n^{1/2}\ MeV }[/math] [math]\displaystyle{ d = 1.0\ m: \ \ \ ( \delta E_n/E_n ) = 0.42\ E_n^{1/2}\ MeV }[/math] [math]\displaystyle{ d = 1.5\ m: \ \ \ ( \delta E_n/E_n ) = 0.28\ E_n^{1/2}\ MeV }[/math] [math]\displaystyle{ d = 2.0\ m: \ \ \ ( \delta E_n/E_n ) = 0.21\ E_n^{1/2}\ MeV }[/math]
