C program for neutron efficiency
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#include <iostream> #include <cmath> using namespace std;
double crossSectionHydrogenFunction(); double numberCarbonFunction(double thickness, const double CUBICCENTIMETERCARBON); double numberHydrogenFunction(double thickness, const double CUBICCENTIMETERHYDROGEN); double crossSectionCarbonFunction(); void efficiencyFunction(double numberHydrogen, double numberCarbon, double crossSectionHydrogen, double crossSectionCarbon, double thickness);
/************************************************************************
* This program is to find the
* efficiency of a neutron detector.
************************************************************************/
double main()
{
double neutronEnergy;
double numberHydrogen;
double numberCarbon;
double crossSectionHydrogen;
double crossSectionCarbon;
double thickness;
const double CUBICCENTIMETERCARBON = 5.23e22;
const double CUBICCENTIMETERHYDROGEN = 4.74e22;
cout << endl; cout << "Enter thickness of detector (in centimeters): "; cin >> thickness;
crossSectionHydrogen = crossSectionHydrogenFunction(); numberCarbon = numberCarbonFunction(thickness, CUBICCENTIMETERCARBON); numberHydrogen = numberHydrogenFunction(thickness, CUBICCENTIMETERHYDROGEN); crossSectionCarbon = crossSectionCarbonFunction();
efficiencyFunction(numberHydrogen, numberCarbon, crossSectionHydrogen, crossSectionCarbon, thickness); }
/********************************************************************** * Equation for cross section of hydrogen according to * equation 15-9 from Radiation Detection and Measurement * by Glenn Knoll *********************************************************************/ double crossSectionHydrogenFunction() { double neutronEnergy; double crossSectionHydrogen;
cout << endl; cout << "Enter neutron energy (in MeV): "; cin >> neutronEnergy;
crossSectionHydrogen = ((4.83e-24 / sqrt(neutronEnergy)) - .578e-24);
return crossSectionHydrogen; }
/********************************************************************** * Equation for calculating the number of Carbons in * the problem per cubic centimeter, dependent on what * the user put in for the thickness of the detector. *********************************************************************/ double numberCarbonFunction(double thickness, const double CUBICCENTIMETERCARBON) { double numberCarbon;
numberCarbon = CUBICCENTIMETERCARBON; return numberCarbon; }
/********************************************************************* * Equation for calculating the number of Hydrogens in * the problem per cubic centimeter, dependent on what * the user put in for the thickness of the detector. ********************************************************************/ double numberHydrogenFunction(double thickness, const double CUBICCENTIMETERHYDROGEN) { double numberHydrogen;
numberHydrogen = CUBICCENTIMETERHYDROGEN; return numberHydrogen; }
/********************************************************************* * Requesting the cross section from the Knoll book, and * then calculating it from barns to centimeters. ********************************************************************/ double crossSectionCarbonFunction() { double crossSectionCarbon;
cout << endl; cout << "Enter the cross section of Carbon by " << "looking in Radiation" << endl << "Detection and Measurement by Glenn Knoll, on" << " page 535, " << endl << "Figure 15-15b (in barns): "; cin >> crossSectionCarbon; crosSectionCarbon = crossSectionCarbon * 1e-24;
return crossSectionCarbon; }
/******************************************************************* * Equation for efficiency according to equation 15-8b * from Radiation Detection and Measurement * by Glenn Knoll ******************************************************************/ void efficiencyFunction(double numberHydrogen, double numberCarbon, double crossSectionHydrogen, double crossSectionCarbon, double thickness) { double efficiency; double nHcH = numberHydrogen * crossSectionHydrogen; double nCcC = numberCarbon * crossSectionCarbon;
efficiency = (((nHcH) / (nHcH + nCcC)) * (1-exp(-(nHcH + nCcC) * thickness))); if(efficiency <= 0) { efficiency = 0; } cout.precision(4); cout << endl; cout << "Therefore, the efficiency of our " << "system is: " << efficiency *100 << "%" << endl; cout << endl; return; }