Differential Cross-Section

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Feynman1stLevel.png


M=M1+M2


iMee=i(e2(p1+p1)μ(p2+p2)μ(p2p2)2e2(p1+p2)μ(p2+p1)μ(p1p2)2)


Mee=e2(P1P2+P1P2+P1P2+P1P2(P2P2)2P1P2+P2P1+P2P2+P1P1(P1P2)2)


Using the fact that P1P2=P1P2P1P1=P2P2P1P2=P2P1


Mee=e2(2P1P2+2P1P2(P222P2P2+P22)2P1P2+2P1P1(P212P1P2+P22))


Mee=e2(2P1P2+2P1P2(P222P2P2+P22)2P1P2+2P1P1(P222P2P1+P21))


Mee=e2(2P1P2+2P1P2(P2P2)22P1P2+2P1P1(P2P1)2)



Mee=e2((P212P1P2+P22)(P21+2P1P2+P22)t(P212P1P1+P21)(P21+2P1P2+P22)u)


Mee=e2(ust+tsu)