Circular Conic Section
If the conic is an circle, e=0. This implies
[math]e=\frac{\sin (\beta)}{\sin (\alpha)}=\frac{\sin (25^{\circ})}{\sin (90-\theta)}=0[/math]
Using the relation
[math]sin(90^{\circ}-\theta)=cos(\theta)[/math]
[math]\frac{sin (25^{\circ})}{0}=cos( \theta) =\infty[/math]
The sector angle will never be perpendicular to the plane of the light cone, so this is not a physical possibility.