Lab 10 RS

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Lab 10 Unregulated power supply


Use a transformer for the experiment.

here is a description of the transformer.

File:TF EIM 241 transformer.pdf

File:IN5230-B-T DataSheet.pdf

Half-Wave Rectifier Circuit

1.)Consider building circuit below.

Determine the components needed in order to make the output ripple have a [math]\displaystyle{ \Delta V }[/math] less than 1 Volt.

The output ripple can be found by [math]\displaystyle{ \Delta V=\frac{I\Delta t}{C} }[/math]

I have used the following components and input parameters:

[math]\displaystyle{ R = 96.9\ k\Omega }[/math]
[math]\displaystyle{ R_L = 98.7\ k\Omega }[/math]
[math]\displaystyle{ R_{scope} = 1\ M\Omega }[/math]
[math]\displaystyle{ C = 2.2\ uF }[/math]

and the following input parameters:


[math]\displaystyle{ \Delta t = 17\ ms\ which\ corresponds\ to\ 60\ Hz }[/math]
[math]\displaystyle{ V_{in} = 24\ V }[/math]


The current through the circuit can be found as [math]\displaystyle{ I = \frac{V_{in}}{R_{tot}} }[/math]

where [math]\displaystyle{ R_{tot} = R + \frac{R_L \cdot \frac{1}{j\omega C}}{R_L + \frac{1}{j\omega C}} = 96.9\ k\Omega + \frac{98.7\ k\Omega \cdot 1.21\ k\Omega)}{98.7\ k\Omega \cdot 1.21\ k\Omega)} = (96.9 + 1.19)\ k\Omega = 98.1\ k\Omega }[/math]


So my output ripple becomes [math]\displaystyle{ \Delta V = \frac{}{} }[/math]


List the components below and show your instructor the output observed on the scope and sketch it below.

Full-Wave Rectifier Circuit

Determine the components needed in order to make the above circuit's output ripple have a [math]\displaystyle{ \Delta V }[/math] less than 0.5 Volt.

List the components below and show your instructor the output observed on the scope and sketch it below.


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