Eγ vs probability with 8 cm of D20

Go Back

$Probability = \sigma \times \rho \times thickness$

$\rho(D _20) = 1 \frac{g}{cm^{3}} \times \frac {20}{18} \times \frac{6.022 \cdot 10^{23}}{20g}\times 2 = 6.6242 \cdot 10^{22}$

$6 MeV = 2200 \cdot 10^{-30} \times 6.6242 \cdot 10^{22} \times 8 cm = 11.77 \cdot 10^{-4}$

$8 MeV = 1776 \cdot 10^{-30} \times 6.6242 \cdot 10^{22} \times 8 cm = 9.51 \cdot 10^{-4}$

$10 MeV = 1409 \cdot 10^{-30} \times 6.6242 \cdot 10^{22} \times 8 cm =7.54 \cdot 10^{-4}$

$12 MeV = 1161 \cdot 10^{-30} \times 6.6242 \cdot 10^{22} \times 8 cm =6.22 \cdot 10^{-4}$

$13 MeV = 1058 \cdot 10^{-30} \times 6.6242 \cdot 10^{22} \times 8 cm =5.66 \cdot 10^{-4}$

$14 MeV = 963 \cdot 10^{-30} \times 6.6242 \cdot 10^{22} \times 8 cm = 5.15 \cdot 10^{-4}$

Go Back