Monte Carlo Binary Collision Approximation

When uranium-235 undergoes fission, the average of the fragment mass is about 118, but it is more probable that the pair will have an unequal distribution in mass. A common pair of fragments from uranium-235 fission is xenon and strontium as shown in the reaction:

$^{235}U+n\rightarrow ^{236}U^{*} \rightarrow ^{140}Xe+^{94}Sr+2n$

Nuclear fission of uranium-235 yields an enormous amount of energy from the fact that the fission products have less total mass than the uranium nucleus, a mass change that is converted to energy by the Einstein relationship $E=mc^2$. Using the Law of Conservation of Energy, we can look at the total energy before and after the fission to determine how much energy is released in this process.

$^{236}_{92}U : 92(938.272\ MeV)+144(939.565\ MeV)\ =\ 221.618\ GeV$ $^{140}_{54}Xe : 54(938.272\ MeV)+86(939.565\ MeV)\ =\ 131.469\ GeV$ $^{94}_{38}Sr : 38(938.272\ MeV)+56(939.565\ MeV)\ =\ 88.269\ GeV$ $2*n : 2(939.565\ MeV)\ =\ 1.879\ GeV$ $-----------------------------$ <math> Energy released=