Moller events WITH Solenoid
LUND file with Moller events (with origin of coordinates occurring at each event)
2 1 1 1 1 0 0.000563654 3.53715 0 6.2002
1 -1 1 11 0 0 0.69 -2.4999 10993.7998 10993.80 0.000511 0 0 0
2 -1 1 11 0 0 -0.69 2.4999 6.5852 7.08 0.000511 0 0 0
From a GEMC run WITH the Solenoid.
We take the phi angle from the Simulated Event momentum.
To find the change in phi we compare it to the final position from Timer Based Tracking.
The final position is the same as the
Transformation Matrix
[math]\left(
\begin{array}{ccc}
\cos (\theta ) & 0 & -\sin (\theta ) \\
0 & 1 & 0 \\
\sin (\theta ) & 0 & \cos (\theta ) \\
\end{array}
\right).\left(
\begin{array}{c}
x \\
y \\
z \\
\end{array}
\right)[/math]
[math]=\left(
\begin{array}{c}
x \cos (\theta )-z \sin (\theta ) \\
y \\
z \cos (\theta )+x \sin (\theta ) \\
\end{array}
\right)[/math]
Phi Shifts
For event #29, in sector 3, the location of the first interaction is given by
Converting -25 degrees to radians,
[math]\theta =-0.436332[/math]
[math]\left(
\begin{array}{ccc}
\cos (\theta ) & 0 & -\sin (\theta ) \\
0 & 1 & 0 \\
\sin (\theta ) & 0 & \cos (\theta ) \\
\end{array}
\right).\left(
\begin{array}{c}
-15.76 \\
0 \\
237.43 \\
\end{array}
\right)[/math]
[math]=\left(
\begin{array}{c}
86.0588 \\
0. \\
221.845 \\
\end{array}
\right)[/math]
Finding [math]\phi =\frac{120\ 2 \pi }{360};[/math] since "sector -1" =3-1=2*60=120 degrees
[math]\left(
\begin{array}{ccc}
\cos (\phi ) & -\sin (\phi ) & 0 \\
\sin (\phi ) & \cos (\phi ) & 0 \\
0 & 0 & 1 \\
\end{array}
\right).\left(
\begin{array}{c}
86.0588 \\
0. \\
221.845 \\
\end{array}
\right)[/math]
[math]\left(
\begin{array}{c}
-43.0294 \\
74.5291 \\
221.845 \\
\end{array}
\right)[/math]
DV_RunGroupC_Moller#Moller_Track_Reconstruction
