Difference between revisions of "Forest UCM Osc Damped"
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::<math> \Rightarrow \frac{dx}{x} = \left ( - \beta + \sqrt{\beta^2 -\omega^2} \right ) dt </math> | ::<math> \Rightarrow \frac{dx}{x} = \left ( - \beta + \sqrt{\beta^2 -\omega^2} \right ) dt </math> | ||
::<math> x= e^{\left ( - \beta + \sqrt{\beta^2 -\omega^2} \right )t} </math> | ::<math> x= e^{\left ( - \beta + \sqrt{\beta^2 -\omega^2} \right )t} </math> | ||
+ | |||
+ | constructing a complete solution from the two solutions (orthogonal functions) above. | ||
+ | |||
+ | ::<math> x= \left ( C_1 e^{ \sqrt{\beta^2 -\omega^2} t} + C_2 e^{ -\sqrt{\beta^2 -\omega^2} t} \right) e^{- \beta t} </math> | ||
[[Forest_UCM_Osc#Damped_Oscillations]] | [[Forest_UCM_Osc#Damped_Oscillations]] |
Revision as of 13:03, 5 October 2014
1-D Damped Oscillaions
Equation of Motion
As in the case of air resistance, assume there is frictional force proportional to the velocity of the oscillation body.
- : in 1-D
or
or
let
- undamped oscillation frequency
- damping constant
then
As see in section Forest_UCM_Osc_SHM#Equation_of_motion, you can determine solutions to the above
by writing the analogous auxilary equation:
Setting the term in parentheses to zero and using the quadratic formula
You have change the second order differential equation into two first order differential equations
constructing a complete solution from the two solutions (orthogonal functions) above.