Difference between revisions of "Forest UCM NLM Oscilations"
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==Step 5: apply Netwon's 2nd Law== | ==Step 5: apply Netwon's 2nd Law== | ||
− | : \sum \vec{F}_ext = \vec{F}_g + \vec{N} = m \left ( \right ) | + | : <math>\sum \vec{F}_ext = \vec{F}_g + \vec{N} = m \left ( \ddot{r} -r\dot{\phi}^2 \right) \hat{r} + \left ( 2\dot{r} \dot{\phi} +r \ddot{\phi} \right ) \hat{\phi}</math> |
+ | |||
+ | For the case of circular motion at constant <math> r (\dot{r} = 0)</math> | ||
+ | |||
+ | :<math>\vec{a} = -r\dot{\phi}^2 \hat{r} + r \ddot{\phi} \hat{\phi} </math> | ||
[[Forest_UCM_NLM#Oscillatiions]] | [[Forest_UCM_NLM#Oscillatiions]] |
Revision as of 12:07, 31 August 2014
Skate boarder in Half pipe
Consider a frictionless skateboard released from the top of a semi-circle (half pipe) and oriented to fall directly towards the bottom. The semi-circle has a radius
and the skateboard has a mass .Note: because the skateboard is frictionless, its wheels are not going to turn.
Step 1: System
The skateboard of mass
is the system.Step 1: Coordinate system
Polar coordinate may be a good coordinate system to use since the skateboard's motion will be along the half circle.
Step 3: Free Body Diagram
Step 4: External Force vectors
Step 5: apply Netwon's 2nd Law
For the case of circular motion at constant