Neutron energy resolution in NaI detector: Difference between revisions

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<math> E_n = \frac{m}{2}\left( \frac{d}{t_n} \right)^2 </math>
<math> E_n = \frac{m}{2}\left( \frac{d}{t_n} \right)^2 </math>


<math> \delta T_{\gamma} = 2.003\ \delta T_n = 2.003\times 1\ MeV = 2.003\ MeV </math>
<math> \delta E_n = -2\ E_n \frac{\delta t_n}{t_n} = -\frac{2 sqrt{2}}{\sqrt{m} d}\ E_n^{3/2} \delta t_n </math>

Revision as of 03:31, 28 April 2012

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[math]\displaystyle{ E_n = \frac{m}{2}\left( \frac{d}{t_n} \right)^2 }[/math]

[math]\displaystyle{ \delta E_n = -2\ E_n \frac{\delta t_n}{t_n} = -\frac{2 sqrt{2}}{\sqrt{m} d}\ E_n^{3/2} \delta t_n }[/math]

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