Difference between revisions of "Geometry (25 MeV LINAC exit port)"

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|<math>\Theta_{kicker}</math>
 
|<math>\Theta_{kicker}</math>
 
|<math>\alpha_{collimator}</math>
 
|<math>\alpha_{collimator}</math>
|<math>AC\ cm</math>
+
|<math>AC</math>
|<math>A_1C_1\ cm</math>
+
|<math>A_1C_1</math>
|<math>BD\ cm</math>
+
|<math>BD</math>
|<math>B_1D_1\ cm</math>
+
|<math>B_1D_1</math>
|<math>FA\ cm</math>
+
|<math>FA</math>
|<math>F_1F\ cm</math>
+
|<math>F_1F</math>
 
|-
 
|-
|<math>\frac{\Theta_{critical}}{2}</math>||<math>1.17^o</math>||<math>0.83^o</math>||<math>2.03^o</math>||4.13||6.78||2.92||4.79||75||143
+
|<math>\frac{\Theta_{critical}}{2}</math>||<math>1.17^o</math>||<math>0.83^o</math>||<math>2.03^o</math>
 +
|4.13 cm||6.78 cm||2.92 cm||4.79 cm||75 cm||143 cm
 
|-
 
|-
|<math>\frac{\Theta_{critical}}{4}</math>||<math>1.17^o</math>||<math>0.82^o</math>||<math>1.43^o</math>||4.13||6.78||1.46||2.40||136||203
+
|<math>\frac{\Theta_{critical}}{4}</math>||<math>1.17^o</math>||<math>0.82^o</math>||<math>1.43^o</math>
 +
|4.13 cm||6.78 cm||1.46 cm||2.40 cm||136 cm||203 cm
 
|-
 
|-
 
|}
 
|}

Revision as of 05:49, 13 June 2010

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Minimum accelerator energy to run experiment

Min energy.png

The minimum energy of accelerator (MeV) is limited by fitting the collimator ([math]r_2[/math]) into the hole ([math]R = 8.73\ cm[/math])

[math]x_2 + r_2 = R[/math]

1) Assuming the collimator diameter is [math]\Theta_C[/math]:

[math]\frac{1}{\sqrt{2}}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) +
       \frac{1}{2}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 33.1\ MeV  [/math]

2) Assuming the collimator diameter is [math]\Theta_C/2[/math]:

[math]\frac{1}{\sqrt{2}}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) +
       \frac{1}{2}\ (286+183)\ \tan\left(\frac{1}{2}\ \frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 26.3\ MeV  [/math]

3) Assuming the collimator diameter is [math]\Theta_C/4[/math]:

[math]\frac{1}{\sqrt{2}}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) +
       \frac{1}{2}\ (286+183)\ \tan\left(\frac{1}{4}\ \frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 22.8\ MeV  [/math]

4) In general:

Plot energy collimatorsize.jpeg

25 MeV geometry

geometry calculation

collimator diameter [math]\Theta_{critical}[/math] [math]\Theta_{kicker}[/math] [math]\alpha_{collimator}[/math] [math]AC[/math] [math]A_1C_1[/math] [math]BD[/math] [math]B_1D_1[/math] [math]FA[/math] [math]F_1F[/math]
[math]\frac{\Theta_{critical}}{2}[/math] [math]1.17^o[/math] [math]0.83^o[/math] [math]2.03^o[/math] 4.13 cm 6.78 cm 2.92 cm 4.79 cm 75 cm 143 cm
[math]\frac{\Theta_{critical}}{4}[/math] [math]1.17^o[/math] [math]0.82^o[/math] [math]1.43^o[/math] 4.13 cm 6.78 cm 1.46 cm 2.40 cm 136 cm 203 cm

geometry pictures

how it looks 1 ([math] \Theta_c/2[/math], box 3"x4" and then pipe 4")

File:Vacuum pipe collimator .png

how it looks 2 ([math] \Theta_c/4[/math], box 3"x4" and then pipe 4")

File:Vacuum pipe collimator .png


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