Megan Homework: Difference between revisions
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12.) <math>\frac{y^{-3}}{y^{3}}</math> | 12.) <math>\frac{y^{-3}}{y^{3}}</math> | ||
13.) <math>\frac{y^{-2}}{y^{-8}}</math> | |||
Revision as of 00:32, 13 April 2010
True/False
- [math]\displaystyle{ \sqrt{a} + \sqrt{a} = \sqrt{a+a} }[/math]
- [math]\displaystyle{ \sqrt{8x} = 2 \sqrt{4x} }[/math]
- [math]\displaystyle{ e^{-1/2} = -\sqrt{e} }[/math]
- [math]\displaystyle{ x^{-2/3} = \sqrt{x^3} }[/math]
- [math]\displaystyle{ (g \cdot f)(x) = g(x)f(x) }[/math]
- [math]\displaystyle{ (g \circ f)(x) = f(g(x)) }[/math]
- if [math]\displaystyle{ f(x) = 4x }[/math] and [math]\displaystyle{ g(x) = \sqrt{x} }[/math]
- [math]\displaystyle{ (g \circ f)(x) = 4 \sqrt{x} }[/math]
- [math]\displaystyle{ (g \circ g)(y) = \sqrt[4]{y} }[/math]
- [math]\displaystyle{ (g \circ f)(z) = (f \circ g)(z) }[/math]
- [math]\displaystyle{ t^2t^3 = t^6 }[/math]
- [math]\displaystyle{ \frac{2x+1}{x+1} = \frac{2x}{x} = 2 }[/math]
Simplify
- [math]\displaystyle{ \frac{2}{2+3\sqrt{2x}} }[/math]
- [math]\displaystyle{ \frac{x}{x^{-2/3}} }[/math]
- [math]\displaystyle{ r^{-1} }[/math]
- [math]\displaystyle{ \frac{x+1}{x^2-1} }[/math]
At what points are the following expressions undefined?
- [math]\displaystyle{ \frac{x-1}{x+1} }[/math]
- [math]\displaystyle{ x^{-1/2} }[/math]
- [math]\displaystyle{ \frac{6}{x^2-1} }[/math]
- [math]\displaystyle{ \frac{2}{|x+1|-1} }[/math]
Problems ||
Simplify
1.) [math]\displaystyle{ \frac{\sqrt{x}+4}{3-\sqrt{x}} }[/math]
2.) [math]\displaystyle{ \frac{x^2}{\sqrt{x}+5} }[/math]
3.) [math]\displaystyle{ \frac{x^2 + 2x +1}{x+1} }[/math]
4.) [math]\displaystyle{ \frac{x^2 -10x + 25}{(x+5)(x-5)} }[/math]
5.) [math]\displaystyle{ \frac{4x^2 - y^2}{2x + y} }[/math]
6.) [math]\displaystyle{ x^2 x^7 }[/math]
7.) [math]\displaystyle{ y^5 y^9 }[/math]
8.) [math]\displaystyle{ x^5 x^{-4} }[/math]
9.) [math]\displaystyle{ x^{-2}x^{-3} }[/math]
10.) [math]\displaystyle{ \frac{x^5}{x^2} }[/math]
11.) [math]\displaystyle{ \frac{y^2}{y^{5}} }[/math]
12.) [math]\displaystyle{ \frac{y^{-3}}{y^{3}} }[/math]
13.) [math]\displaystyle{ \frac{y^{-2}}{y^{-8}} }[/math]