Megan Homework: Difference between revisions
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#<math>\sqrt{8x} = 2 \sqrt{4x}</math> | #<math>\sqrt{8x} = 2 \sqrt{4x}</math> | ||
#<math>e^{-1/2} = -\sqrt{e}</math> | #<math>e^{-1/2} = -\sqrt{e}</math> | ||
#<math>x^{-2/3} = \sqrt{x^3}</math> | |||
# <math>(g \cdot f)(x) = g(x)f(x) </math> | # <math>(g \cdot f)(x) = g(x)f(x) </math> | ||
# <math>(g \circ f)(x) = f(g(x)) </math> | # <math>(g \circ f)(x) = f(g(x)) </math> | ||
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#<math>t^2t^3 = t^6</math> | #<math>t^2t^3 = t^6</math> | ||
#<math>\frac{2x+1}{x+1} = \frac{2x}{x} = 2</math> | #<math>\frac{2x+1}{x+1} = \frac{2x}{x} = 2</math> | ||
===Simplify=== | |||
#<math>\frac{2}{2+3sqrt{2x}}</math> | |||
#<math>\frac{x}{x^{-2/3}}</math> | |||
#<math>r^{-1}</math> | |||
#<math>\frac{x+1}{x^2-1}</math> | |||
===At what points are the following expressions undefined?=== | |||
#<math>\frac{x-1}{x+1}</math> | |||
#<math>x^{-1/2}</math> | |||
#<math>\frac{6}{x^2-1}</math> | |||
#<math>\frac{2}{|x+1|-1}</math> | |||
Revision as of 23:59, 12 April 2010
True/False
- [math]\displaystyle{ \sqrt{a} + \sqrt{a} = \sqrt{a+a} }[/math]
- [math]\displaystyle{ \sqrt{8x} = 2 \sqrt{4x} }[/math]
- [math]\displaystyle{ e^{-1/2} = -\sqrt{e} }[/math]
- [math]\displaystyle{ x^{-2/3} = \sqrt{x^3} }[/math]
- [math]\displaystyle{ (g \cdot f)(x) = g(x)f(x) }[/math]
- [math]\displaystyle{ (g \circ f)(x) = f(g(x)) }[/math]
- if [math]\displaystyle{ f(x) = 4x }[/math] and [math]\displaystyle{ g(x) = \sqrt{x} }[/math]
- [math]\displaystyle{ (g \circ f)(x) = 4 \sqrt{x} }[/math]
- [math]\displaystyle{ (g \circ g)(y) = \sqrt[4]{y} }[/math]
- [math]\displaystyle{ (g \circ f)(z) = (f \circ g)(z) }[/math]
- [math]\displaystyle{ t^2t^3 = t^6 }[/math]
- [math]\displaystyle{ \frac{2x+1}{x+1} = \frac{2x}{x} = 2 }[/math]
Simplify
- [math]\displaystyle{ \frac{2}{2+3sqrt{2x}} }[/math]
- [math]\displaystyle{ \frac{x}{x^{-2/3}} }[/math]
- [math]\displaystyle{ r^{-1} }[/math]
- [math]\displaystyle{ \frac{x+1}{x^2-1} }[/math]
At what points are the following expressions undefined?
- [math]\displaystyle{ \frac{x-1}{x+1} }[/math]
- [math]\displaystyle{ x^{-1/2} }[/math]
- [math]\displaystyle{ \frac{6}{x^2-1} }[/math]
- [math]\displaystyle{ \frac{2}{|x+1|-1} }[/math]