Difference between revisions of "Megan Homework"
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(Created page with '===True/False=== #<math>\sqrt{a} + \sqrt{a} = \sqrt{a+a}</math> #<math>\sqrt{8x} = 2 \sqrt{4x}</math>') |
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#<math>\sqrt{a} + \sqrt{a} = \sqrt{a+a}</math> | #<math>\sqrt{a} + \sqrt{a} = \sqrt{a+a}</math> | ||
#<math>\sqrt{8x} = 2 \sqrt{4x}</math> | #<math>\sqrt{8x} = 2 \sqrt{4x}</math> | ||
+ | #<math>e^{-1/2} = -\sqrt{e}</math> | ||
+ | # <math>(g \cdot f)(x) = g(x)f(x) </math> | ||
+ | # <math>(g \circ f)(x) = f(g(x)) </math> | ||
+ | #if <math>f(x) = 4x</math> and <math>g(x) = \sqrt{x} </math> | ||
+ | ## <math>(g \circ f)(x) = 4 \sqrt{x} </math> | ||
+ | ## <math>(g \circ g)(y) = \sqrt[4]{y} </math> | ||
+ | ## <math>(g \circ f)(z) = (f \circ g)(z) </math> | ||
+ | #<math>t^2t^3 = t^6</math> | ||
+ | #<math>\frac{2x+1}{x-1} = \frac{2x}{x} = 2</math> |
Revision as of 21:59, 12 April 2010
True/False
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