Difference between revisions of "Electric QuadrupoleMoment Forest NuclPhys I"

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As in the dipole calculation we assume that the object is in a state such that its maximum total angular momentum is along the z-axis.
 
As in the dipole calculation we assume that the object is in a state such that its maximum total angular momentum is along the z-axis.
  
or <math>\psi</math>
+
or <math>\Psi_{jm} = \Psi_{jj}</math>
 +
 
 +
 
 +
then
 +
 
 +
<math>Q = < \Psi_{jj} |3z^2 - r^2|\Psi_{jj}></math>
 +
 
 +
From definition of quadrupole moment for a single charged object/particle.
 +
 
 +
The origin of this comes from electron-statics.
 +
 
 +
You expand the electric potential in terms of spherical harmonics.
 +
 
 +
<math>\Phi(\vec{r}) = {\Sigma_{l=0}}^{\infty} {\Sigma_{m=-l}}^{l} \frac{4\pi}{2l + 1} q_{lm} \frac{Y_{lm}(\theta \psi)}{r^{l+1}}</math>  
 +
 
 +
because
 +
 
  
  
 
[[Forest_NucPhys_I]]
 
[[Forest_NucPhys_I]]

Revision as of 04:36, 7 April 2009

Electric Quadrupole Moment of a Nucleus

Pages 104-111

As in the dipole calculation we assume that the object is in a state such that its maximum total angular momentum is along the z-axis.

or [math]\Psi_{jm} = \Psi_{jj}[/math]


then

[math]Q = \lt \Psi_{jj} |3z^2 - r^2|\Psi_{jj}\gt [/math]

From definition of quadrupole moment for a single charged object/particle.

The origin of this comes from electron-statics.

You expand the electric potential in terms of spherical harmonics.

[math]\Phi(\vec{r}) = {\Sigma_{l=0}}^{\infty} {\Sigma_{m=-l}}^{l} \frac{4\pi}{2l + 1} q_{lm} \frac{Y_{lm}(\theta \psi)}{r^{l+1}}[/math]

because


Forest_NucPhys_I