Difference between revisions of "Plastic Scintillator Calculation"

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Molecules per <math> cm^2 = \frac{Molecules}{cm^3} * Thickness </math>
 
Molecules per <math> cm^2 = \frac{Molecules}{cm^3} * Thickness </math>
  
Weighted cross-section <math>= (\sigma_{elec}C + \sigma_{nucleus}C) + 2(\sigma_{elec}H + \sigma_{nucleus}H)</math>  
+
Weighted cross-section <math> (\sigma_w) = (\sigma_{elec}C + \sigma_{nucleus}C) + 2(\sigma_{elec}H + \sigma_{nucleus}H)</math>  
 +
 
 +
Probability of interaction <math>= \sigma_w
  
 
[http://wiki.iac.isu.edu/index.php/PhotoFission_with_Polarized_Photons_from_HRRL Go Back]
 
[http://wiki.iac.isu.edu/index.php/PhotoFission_with_Polarized_Photons_from_HRRL Go Back]

Revision as of 23:48, 4 February 2009

Below is the calculations done to determine the probability of pair production depending on thickness of the scintillator.

Molecules per [math] cm^3 = \frac{grams CH_{2}}{cm^3} * \frac{mol}{gram} * \frac{N[A]}{mol} [/math]

Molecules per [math] cm^2 = \frac{Molecules}{cm^3} * Thickness [/math]

Weighted cross-section [math] (\sigma_w) = (\sigma_{elec}C + \sigma_{nucleus}C) + 2(\sigma_{elec}H + \sigma_{nucleus}H)[/math]

Probability of interaction <math>= \sigma_w

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