Thickness of Lead to block photons: Difference between revisions

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<math>\frac{h _2}{84.56 + d} = tan(1.95 + .25 \cdot 1.95) => h _2 = .042568d + 3.599557</math>
<math>\frac{h _2}{84.56 + d} = tan(1.95 + .25 \cdot 1.95) => h _2 = .042568d + 3.599557</math>


<math>tan \theta = \frac{h _1}{4.56 cm} => 25.6^{\circ}</math>
<math>tan \theta = \frac{2.1589 cm}{4.56 cm} => 25.6^{\circ}</math>


<math>tan \theta = \frac{h _2}{4.56 cm + d} => tan (25.6^{\circ}) =\frac{.042568d + 3.599557}{d + 4.56 cm}</math>
<math>tan \theta = \frac{h _2}{4.56 cm + d} => tan (25.6^{\circ}) =\frac{.042568d + 3.599557}{d + 4.56 cm}</math>


∴ <math>\textbf{the}</math> <math>\textbf{thickness}</math> <math>\textbf{of}</math> <math>\textbf{the}</math> <math>\textbf{lead = 3.24 cm}</math>
∴ <math>\textbf{the}</math> <math>\textbf{thickness}</math> <math>\textbf{of}</math> <math>\textbf{the}</math> <math>\textbf{lead = 3.24 cm}</math>

Revision as of 13:11, 5 June 2008

[math]\displaystyle{ \frac{h _1}{84.56 cm} = tan(1.95 \times .25 \cdot 1.95) => h _1 = 2.1589 cm }[/math]

[math]\displaystyle{ \frac{h _2}{84.56 + d} = tan(1.95 + .25 \cdot 1.95) => h _2 = .042568d + 3.599557 }[/math]

[math]\displaystyle{ tan \theta = \frac{2.1589 cm}{4.56 cm} => 25.6^{\circ} }[/math]

[math]\displaystyle{ tan \theta = \frac{h _2}{4.56 cm + d} => tan (25.6^{\circ}) =\frac{.042568d + 3.599557}{d + 4.56 cm} }[/math]

∴ [math]\displaystyle{ \textbf{the} }[/math] [math]\displaystyle{ \textbf{thickness} }[/math] [math]\displaystyle{ \textbf{of} }[/math] [math]\displaystyle{ \textbf{the} }[/math] [math]\displaystyle{ \textbf{lead = 3.24 cm} }[/math]