Difference between revisions of "Thickness of Lead to block photons"

From New IAC Wiki
Jump to navigation Jump to search
 
Line 7: Line 7:
 
<math>tan \theta = \frac{h _2}{4.56 cm + d} => tan 25.6 =\frac{.042568d + 3.599557}{d + 4.56 cm}</math>
 
<math>tan \theta = \frac{h _2}{4.56 cm + d} => tan 25.6 =\frac{.042568d + 3.599557}{d + 4.56 cm}</math>
  
∴ the thickness of the lead = 3.24 cm
+
<math>\textbf{the}</math> <math>\textbf{thickness}</math> <math>\textbf{of}</math> <math>\textbf{the}</math> <math>\textbf{lead = 3.24 cm}</math>

Revision as of 13:10, 5 June 2008

[math]\frac{h _1}{84.56 cm} = tan(1.95 \times .25 \cdot 1.95) =\gt h _1 = 2.1589 cm[/math]

[math]\frac{h _2}{84.56 + d} = tan(1.95 + .25 \cdot 1.95) =\gt h _2 = .042568d + 3.599557[/math]

[math]tan \theta = \frac{h _1}{4.56 cm} =\gt 25.6^{\circ}[/math]

[math]tan \theta = \frac{h _2}{4.56 cm + d} =\gt tan 25.6 =\frac{.042568d + 3.599557}{d + 4.56 cm}[/math]

[math]\textbf{the}[/math] [math]\textbf{thickness}[/math] [math]\textbf{of}[/math] [math]\textbf{the}[/math] [math]\textbf{lead = 3.24 cm}[/math]