Revision as of 16:44, 4 June 2008

We're looking to see which is better for letting photons through, Carbon or Aluminum.

20 MeV for Carbon

range is [math]\displaystyle{ 10.49 \frac{g}{cm^{3}} }[/math]

density of Carbon = [math]\displaystyle{ ~2.3 \frac{g}{cm^{3}} }[/math]

thickness = [math]\displaystyle{ \frac{range}{density} = \frac{10.49}{2.3} = 4.56 cm }[/math]

Therefore, the thickness of our Carbon is 4.56 cm

n = [math]\displaystyle{ 2.3 \frac{g}{cm^{3}} \times \frac{6.022 \cdot 10^{23} atoms}{12 g} = 1.2 \cdot 10^{23} \frac{atoms}{cm^{3}} }[/math]

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 We're looking to see which is better for letting photons through, Carbon or Aluminum.
-MeV for Carbon
-range is 10.49 \frac{g}{cm^{3}}
+= 20 MeV for Carbon =
-density of Carbon = ~2.3 \frac{g}{cm^{3}}
-thickness = \frac{range}{density} = \frac{10.49}{2.3} = 4.56 cm^{2}
+range is <math>10.49 \frac{g}{cm^{3}}</math>
+density of Carbon = <math>~2.3 \frac{g}{cm^{3}}</math>
+thickness = <math>\frac{range}{density} = \frac{10.49}{2.3} = 4.56 cm</math>
+Therefore, the thickness of our Carbon is 4.56 cm
+= 10 MeV hitting 4.56 cm of Carbon =
+n = <math>2.3 \frac{g}{cm^{3}} \times \frac{6.022 \cdot 10^{23} atoms}{12 g} = 1.2 \cdot 10^{23} \frac{atoms}{cm^{3}}</math>