Difference between revisions of "Using Carbon or Aluminum to block photons"
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We're looking to see which is better for letting photons through, Carbon or Aluminum. | We're looking to see which is better for letting photons through, Carbon or Aluminum. | ||
− | 20 MeV for Carbon | + | |
− | range is 10.49 \frac{g}{cm^{3}} | + | = 20 MeV for Carbon = |
− | density of Carbon = ~2.3 \frac{g}{cm^{3}} | + | |
− | thickness = \frac{range}{density} = \frac{10.49}{2.3} = 4.56 cm^{2} | + | |
+ | range is <math>10.49 \frac{g}{cm^{3}}</math> | ||
+ | |||
+ | density of Carbon = <math>~2.3 \frac{g}{cm^{3}}</math> | ||
+ | |||
+ | thickness = <math>\frac{range}{density} = \frac{10.49}{2.3} = 4.56 cm</math> | ||
+ | |||
+ | Therefore, the thickness of our Carbon is 4.56 cm | ||
+ | |||
+ | = 10 MeV hitting 4.56 cm of Carbon = | ||
+ | |||
+ | n = <math>2.3 \frac{g}{cm^{3}} \times \frac{6.022 \cdot 10^{23} atoms}{12 g} = 1.2 \cdot 10^{23} \frac{atoms}{cm^{3}}</math> |
Revision as of 16:44, 4 June 2008
We're looking to see which is better for letting photons through, Carbon or Aluminum.
20 MeV for Carbon
range is
density of Carbon =
thickness =
Therefore, the thickness of our Carbon is 4.56 cm
10 MeV hitting 4.56 cm of Carbon
n =