Quantum Qual Problems: Difference between revisions
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In our case, using separation of variables, we will get 3 differential equations for x, y and z. W(x,y,z)=w(x)w(y)w(z)<br> | In our case, using separation of variables, we will get 3 differential equations for x, y and z. W(x,y,z)=w(x)w(y)w(z)<br> | ||
<math>\frac{d^2 w(x)}{dx^2} + c^2 w(x) = 0</math><br> | <math>\frac{d^2 w(x)}{dx^2} + c^2 w(x) = 0</math>(1)<br> | ||
The same will be for y and z.<br> | The same will be for y and z.<br> | ||
Solution of equation (1) is following <br> | Solution of equation (1) is following <br> | ||
<math>w(x) = A\sin</math> | <math>w(x) = A\sin(cx)+B\cos(cx)</math><br> | ||
<math>w(y) = C\sin(cy)+D\cos(cy)</math><br> | |||
<math>w(z) = E\sin(cz)+F\cos(cz)</math><br> | |||
Revision as of 02:50, 16 August 2007
1.) Given a quantum mechanical particle of mass [math]\displaystyle{ M }[/math] confined inside a box of sides [math]\displaystyle{ a,b,c }[/math]. The particle is allowed to move freely between [math]\displaystyle{ 0 <x < a, 0< y< b }[/math] and [math]\displaystyle{ 0<z<c }[/math].
- Use the time-independent Schrodinger equation for this problem to obtain the general form for the eigenfunctions of the particle
- Now apply boundary conditions to obtain the specific eigenfunctions and eigenenergies for this specific problem.
- Assume [math]\displaystyle{ a=b=c }[/math] and find the first 6 eigenenergies of the problem in terms of the box side length ([math]\displaystyle{ a }[/math]), the particle mass ([math]\displaystyle{ M }[/math]) and standard constants. What are their quantum number? Make a sketch of the eigenvalue spectrum, a table listing these eigenenergies and the quantum numbers of all the states that correspond to them.
Solution:
2.)
[math]\displaystyle{ [- \frac{h^2}{2m}\Delta^2 + V]W(x,y,z)=E W(x,y,z) }[/math]
In our case, using separation of variables, we will get 3 differential equations for x, y and z. W(x,y,z)=w(x)w(y)w(z)
[math]\displaystyle{ \frac{d^2 w(x)}{dx^2} + c^2 w(x) = 0 }[/math](1)
The same will be for y and z.
Solution of equation (1) is following
[math]\displaystyle{ w(x) = A\sin(cx)+B\cos(cx) }[/math]
[math]\displaystyle{ w(y) = C\sin(cy)+D\cos(cy) }[/math]
[math]\displaystyle{ w(z) = E\sin(cz)+F\cos(cz) }[/math]