Difference between revisions of "LB Se-79 Soil Analysis"
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==Histogram analysis== | ==Histogram analysis== | ||
The most active sample was the 10% Se/soil mixture's pure selenium witness pellet, so let's analyze that first. The histogram for the sample from 615<t<1115 s is shown below. | The most active sample was the 10% Se/soil mixture's pure selenium witness pellet, so let's analyze that first. The histogram for the sample from 615<t<1115 s is shown below. | ||
+ | |||
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+ | The line in the stats box labeled "integral" represents the total number of counts in the window, which is | ||
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+ | I = 7787 <math> \pm </math> 88.24 Counts | ||
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+ | and the background is | ||
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+ | B = 5053.2 <math> \pm </math> 60.6 Counts | ||
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+ | Now subtract the background from the total number of counts in the window | ||
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+ | N = 2733.8 <math> \pm </math> 107.05 | ||
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+ | Now divide by the runtime to get the activity | ||
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+ | A = <math> \frac{2733.8 \pm 107.05}{500} = 5.5 \pm 0.2 </math> | ||
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+ | Note this is the measurement some time after the beam was turned off, so we can correct this back using the known half life of Se-79m (<math> \lambda </math> = 0.0029 <math> \pm </math> 0.00008 <math> s^{-1} </math> |
Revision as of 20:18, 15 October 2018
Below is a description of how the activity of the Se-79 in the May 2017 soil/Se was determined.
Activity of Se-79m
First, find the activity of the Se-79m state which has a half life of 3.92
0.01 minutes. The line of interest here is 95.73 0.03 keVHistogram analysis
The most active sample was the 10% Se/soil mixture's pure selenium witness pellet, so let's analyze that first. The histogram for the sample from 615<t<1115 s is shown below.
The line in the stats box labeled "integral" represents the total number of counts in the window, which is
I = 7787
88.24 Countsand the background is
B = 5053.2
60.6 CountsNow subtract the background from the total number of counts in the window
N = 2733.8
107.05Now divide by the runtime to get the activity
A =
Note this is the measurement some time after the beam was turned off, so we can correct this back using the known half life of Se-79m (
= 0.0029 0.00008