Difference between revisions of "LB SageBrushWork PostDefense"
| Line 33: | Line 33: | ||
[[File:10Percent SeSage TimingCutInfo 1DHistogram.png|200px]] | [[File:10Percent SeSage TimingCutInfo 1DHistogram.png|200px]] | ||
| + | |||
| + | The time cut information is as follows | ||
| + | |||
| + | 0-300 (Mixture) | ||
| + | 300-360 (Co-60) | ||
| + | 400-640 ( Pure Se) | ||
| + | 680-710 (Co-60) | ||
| + | 730-1020 (Mixture) | ||
| + | 1030-1080 (Co-60) | ||
| + | 1100-1360 ( Pure Se) | ||
| + | 1400-1440 (Co-60) | ||
| + | 1480-1775 (Mixture) | ||
| + | 1800-1840 (Co-60) | ||
| + | 1875-2150 (Pure Se) | ||
| + | 2190-2220 (Co-60) | ||
| + | 2250-2550 (Mixture) | ||
| + | 2590-2620 (Co-60) | ||
| + | 2650-2930 (Pure Se) | ||
| + | 2950-3000 (Co-60) | ||
| + | 3050-3300 (Mixture) | ||
| + | 3390-3350 (Co-60) | ||
| + | 3400-3690 (Pure Se) | ||
| + | 3700-3750 (Co-60) | ||
| + | 3775-4050 (Mixture) | ||
| + | 4060-4100 (Co-60) | ||
| + | 4120-4400 (Pure Se) | ||
| + | 4420-4470 (Co-60) | ||
| + | 4480-4770 (Mixture) | ||
| + | 4790-4820 (Co-60) | ||
| + | 4840-5130 (Pure Se) | ||
==0.1% Sage/Se Mixture Time Cuts== | ==0.1% Sage/Se Mixture Time Cuts== | ||
Revision as of 19:16, 27 August 2018
Time Cuts
The first step in the PAA process is to identify the time cuts used for the split run. This must be done for all samples (50%,10%,0.1%, and 0.04%) Let's do the 50% sample first
50% Sage/Se Mixture Time Cuts
The 50% Se/Sage mixture was measure on Detector B (unshielded, so watch the SNR) on 5/24/17 for a total of 2130.540 seconds. The outer pure witness Se was measure first, and sub-run was roughly 300 seconds for the samples of interest, and 60 seconds for the Co-60 flag. The root command used to draw the timing information was
TTree* tree = MPA;
MPA->Draw("evt.Chan:evt.Sec>>hist2","evt.ADCid == 1");
which produced the histogram below
This seems a little sloppy, lets try a 1D histogram instead to see if the cuts are more clear
ROOT Command: MPA->Draw("evt.Sec>>hist","ADCid==1","");
This produced the histogram below
This seems much cleaner and clearly shows the time cuts
10% Sage/Se Mixture Time Cuts
The 10% Se/Sage mixture was measured on Detector A (shielded) on 5/25/17 for a total of 5136.343 seconds. The mixture was measured first, and a sub-run was roughly 300 seconds for the Se samples and 60 seconds for the Co-60 flag. The root commands used were
TTree* tree = MPA;
MPA->Draw("evt.Chan:evt.Sec>>hist2","evt.ADCid == 0");
The time cut information is as follows
0-300 (Mixture) 300-360 (Co-60) 400-640 ( Pure Se) 680-710 (Co-60) 730-1020 (Mixture) 1030-1080 (Co-60) 1100-1360 ( Pure Se) 1400-1440 (Co-60) 1480-1775 (Mixture) 1800-1840 (Co-60) 1875-2150 (Pure Se) 2190-2220 (Co-60) 2250-2550 (Mixture) 2590-2620 (Co-60) 2650-2930 (Pure Se) 2950-3000 (Co-60) 3050-3300 (Mixture) 3390-3350 (Co-60) 3400-3690 (Pure Se) 3700-3750 (Co-60) 3775-4050 (Mixture) 4060-4100 (Co-60) 4120-4400 (Pure Se) 4420-4470 (Co-60) 4480-4770 (Mixture) 4790-4820 (Co-60) 4840-5130 (Pure Se)
0.1% Sage/Se Mixture Time Cuts
The 0.1% Se/Sage mixture was measured on Detector A (shielded) on 5/24/17 for a total of 2130.540 seconds. The mixture was measured first, and a sub-run was roughly 300 seconds for the Se samples and 60 seconds for the Co-60 flag. The root commands used were
TTree* tree = MPA;
MPA->Draw("evt.Chan:evt.Sec>>hist2","evt.ADCid == 0");
which produced the histogram below
This seems a little sloppy, so let's repeat the procedure for the 50% sample
ROOT Command:ROOT Command: MPA->Draw("evt.Sec>>hist","ADCid==0","");
This produced the histogram below
This is again much better than the 2D histogram.