Difference between revisions of "Relativistic Frames of Reference"
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<center><math>c=\frac{\sqrt{(\Delta x')^2+(\Delta y')^2+(\Delta z')^2}}{\Delta t'}</math></center> | <center><math>c=\frac{\sqrt{(\Delta x')^2+(\Delta y')^2+(\Delta z')^2}}{\Delta t'}</math></center> | ||
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We can rewrite this as | We can rewrite this as | ||
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− | <center><math>c^2=\frac{(\Delta x')^2+(\Delta y')^2+(\Delta z')^2}{(\Delta t')^2}</math></center> | + | <center><math>c^2=\frac{(\Delta x')^2+(\Delta y')^2+(\Delta z')^2}{(\Delta t')^2}\ \ \ \ \c^2=\frac{(\Delta x)^2+(\Delta y)^2+(\Delta z)^2}{(\Delta t)^2}</math></center> |
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+ | <center><math>c^2 \Delta t^{'2}=(\Delta x')^2+(\Delta y')^2+(\Delta z')^2\ \ \ \ \c^2 \Delta t^{2}=(\Delta x)^2+(\Delta y)^2+(\Delta z)^2</math></center> | ||
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Revision as of 03:41, 3 June 2017
Relativistic Frames of Reference
From the Galilean description of motion for a frame of reference moving relative to another frame considered stationary we know that
Using Einstein's Theory of Relativity, we know that the speed of light is a constant, c, for all reference frames. In the unprimed frame, from the definition of speed:
where
Using the distance equation in a Cartesian coordinate system, the equation for the speed of light becomes
Following the postulate of Special Relativity, this implies for the primed frame
We can rewrite this as