Niowave Report 11-30-2015: Difference between revisions

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==Optimal Thickness==
==Optimal Thickness==
 
A 10 MeV electron beam with a 1cm radius uniform cylindrical spatial distribution impinges a windowless PbBi target. The target thickness is changed to determine the optimal thickness to emmitt positrons from the downstream surface of the PbBi target.
2mm thick PbBi, 10 MeV, 1 cm cylindrical incident electron distribution
 
G4beamline pencil beam 10 cm radius  
<pre>
beam ellipse particle=e- nEvents=1000000 beamZ=0.0 beamX=0. beamY=0. \
        sigmaX=10.0 sigmaY=10.0 sigmaXp=0.000 sigmaYp=0.000 \
      meanMomentum=10. sigmaE=0. maxR=10.
</pre>
 
Incident Electron spatial distribution and energy
 
[[File:PbBi_5-1-15_X-Yposition.png | 200 px]][[File:PbBi_5-1-15_Ein.png | 200 px]]
 
Positron and Electron Momentum after the converter


[[File:PbBi_5-1-15_Ppositron.png | 200 px]][[File:PbBi_5-1-15_Pelectron.png | 200 px]]
[[File:PbBi_5-1-15_Ppositron.png | 200 px]][[File:PbBi_5-1-15_Pelectron.png | 200 px]]

Revision as of 19:18, 28 November 2015

Overview

10 MeV electron beam

3.48 cm diameter beam pipe

Target optimization

Optimal Thickness

A 10 MeV electron beam with a 1cm radius uniform cylindrical spatial distribution impinges a windowless PbBi target. The target thickness is changed to determine the optimal thickness to emmitt positrons from the downstream surface of the PbBi target.


Optimal Solenoidal Field

Beam Pipe heating

The energy deposited by electrons scattered into a 3.48 diameter stainless steel beam pipe (1.65 mm thick) from a PbBi target as a function of a uniform Solenoidal magnetic field.

The histogram is binned in 100 (10 cm) bin widths. The surface area becomes [math]\displaystyle{ 10 cm \times 2 \pi 3.48/2 = 109.33 cm^2 }[/math]


To convert From Mev/ e- to kW/cm^2 assuming a current of 1mA (10^-3 C/s) you

[math]\displaystyle{ \left( \frac{\mbox{MeV}}{\mbox{cm}^2 \mbox{e}^-}\right) \times \left( \frac{ \mbox{e}^-}{1.6 \times 10^{-19}\mbox{C}} \right ) \times \left( \frac{1 \times 10^{-3} \mbox{C}}{\mbox{s}} \right ) \times \left( \frac{1.6 \times 10^{-13}\mbox{W} \cdot \mbox{ s}}{\mbox{MeV} }\right ) }[/math]

[math]\displaystyle{ \left( \frac{\mbox{keV}}{\mbox{cm}^2 \mbox{e}^-}\right) = \left( \frac{\mbox{W} }{\mbox{cm}^2 } \right ) }[/math]


Energy deposited (MeV) along a 1 m long beam pipe of stainless steel 1.65 mm thick.

Solenoid Description

A 10 MeV electron beam with a radius of 0.5 cm was incident on a 2 mm thick PbBi target. The target is positioned at Z = -901 mm.



G4Beamline_PbBi#Reports