Difference between revisions of "Solution details"

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so  
 
so  
  
<math> \napla^2 V = \labmda_L^2 V </math>
+
<math> \nabla^2 V = \labmda_L^2 V </math>

Revision as of 18:02, 25 October 2013

asymptotic solution details for Boltzmann equation for a hole has a uniform electric field

(2x2+2x2)n + DL2z2 - Wz n = 0

Steps to solve Boltzmann equation

for the previous equation let consider the asymptotic solution has the form:

n(x,y,z)=eλLzV(x,y,z)

so

2V=\labmda2LV