511 keV photon attenuation in tungsten: Difference between revisions

Revision as of 03:55, 20 September 2012

For 0.5 MeV photon, [math]\displaystyle{ \mu / \rho = 0.1378~(cm^2/g) }[/math], [math]\displaystyle{ \mu_{en} / \rho = 0.0744~(cm^2/g) }[/math]

Revision as of 03:54, 20 September 2012 view source Setisadi (talk \| contribs) 6,202 edits No edit summary ← Older edit		Revision as of 03:55, 20 September 2012 view source Setisadi (talk \| contribs) 6,202 edits No edit summary Newer edit →
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	[http://physics.nist.gov/PhysRefData/XrayMassCoef/tab3.html Photon attenuation in elemental matters]		[http://physics.nist.gov/PhysRefData/XrayMassCoef/tab3.html Photon attenuation in elemental matters]

	For 0.5 MeV photon, <math>\mu / \~~rou~~ = 0.1378~(cm^2/g)</math>		For 0.5 MeV photon, <math>\mu / \rho = 0.1378~(cm^2/g)</math>, <math>\mu_{en} / \rho = 0.0744~(cm^2/g)</math>