Difference between revisions of "Neutron energy resolution in NaI detector"

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  <math> E_n = \frac{m}{2}\left( \frac{d}{t_n} \right)^2 </math>
 
  <math> E_n = \frac{m}{2}\left( \frac{d}{t_n} \right)^2 </math>
  
−
  <math> \delta E_n = -2\ E_n \frac{\delta t_n}{t_n} = -\frac{2 \sqrt{2}}{\sqrt{m} d}\ E_n^{3/2} \delta t_n </math>
+
  <math> \delta E_n = -\frac{2 \sqrt{2}}{\sqrt{m} d}\ E_n^{3/2} \delta t_n </math>
  
  

Revision as of 03:38, 28 April 2012

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[math] E_n = \frac{m}{2}\left( \frac{d}{t_n} \right)^2 [/math]

[math] \delta E_n = -\frac{2 \sqrt{2}}{\sqrt{m} d}\ E_n^{3/2} \delta t_n [/math]


  • [math] \delta t_n = 15\ ns[/math]
  • [math] mc^2 = 938\ MeV [/math]


[math] d = 0.5 m: \ \ \   \delta E_n = 0.83\ E_n^{3/2}\ MeV [/math]

[math] d = 1.0 m: \ \ \   \delta E_n = 0.42\ E_n^{3/2}\ MeV [/math]

[math] d = 1.5 m: \ \ \   \delta E_n = 0.28\ E_n^{3/2}\ MeV [/math]

[math] d = 2.0 m: \ \ \   \delta E_n = 0.21\ E_n^{3/2}\ MeV [/math]
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