Difference between revisions of "252CF"
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<math> x = \frac{1\ g/cm^2} {11.35\ g/cm^3} \approx 0.1\ cm </math> | <math> x = \frac{1\ g/cm^2} {11.35\ g/cm^3} \approx 0.1\ cm </math> | ||
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| + | * We need 0.1 cm of Pb to completely stop gammas from 252CF | ||
Revision as of 04:31, 21 March 2012
- We have 0.87 MeV gammas from 252CF
- From W.R. Leo the range for 1 MeV gammas in Pb is about 1
- We need 0.1 cm of Pb to completely stop gammas from 252CF