Difference between revisions of "D2O photodisintegration simulation"
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[[File:D2_neutron_yield2.gif | 500 px]] [[File:D2_neutron_yield_cut.gif | 450 px]] | [[File:D2_neutron_yield2.gif | 500 px]] [[File:D2_neutron_yield_cut.gif | 450 px]] | ||
− | So, if we apply the energy cut in neutron spectrum which is a sum of neutrons coming from <math>O16(\gamma,n)O15</math> and <math>D_2(\gamma,n)p</math> reactions at (0MeV)<E<=5MeV, then the ratio of unpolarized photons from <math>O16(\gamma,n)O15</math> and polarized photons from <math>D_2(\gamma,n)p</math> will be <math>855/15128=0.056</math>. In the same time we will loose <math>(16799-15128)/15128=11%</math> of the "good" neutrons produced in <math>D_2(\gamma,n)p</math> reaction. | + | So, if we apply the energy cut in neutron spectrum which is a sum of neutrons coming from <math>O16(\gamma,n)O15</math> and <math>D_2(\gamma,n)p</math> reactions at (0MeV)<E<=5MeV, then the ratio of unpolarized photons from <math>O16(\gamma,n)O15</math> and polarized photons from <math>D_2(\gamma,n)p</math> will be <math>855/15128=0.056</math>. In the same time we will loose <math>(16799-15128)/15128=11%</math> of the "good" neutrons produced in <math>D_2(\gamma,n)p</math> reaction. |
+ | |||
+ | I will verify if those spectra and all the ratios are the same in the case where we use the geometrical constrains applied by the detectors placement. |
Revision as of 01:42, 11 April 2011
The result of GEANT4 simulation of neutron photoproduction on deuterium and oxygen-16 is presented below:
Neutron yield ( ) from (90% concentration) in reaction is presented below. Initially brem photons with 25 MeV end-point energy were thrown on the target. 410 neutrons initially produced got absorbed in the target (E=0MeV) and 2509 neutrons will likely escape the target. Figure in blue on the left is the total energy spectrum of neutrons created in reaction . Figure in blue on the right is the neutron energy spectrum with energy cut applied.
Neutron yield (
) from (90% concentration) in reaction is presented below. Initially brem photons with 25 MeV end-point energy were thrown on the target. 857 neutrons initially produced got absorbed in the target (E=0MeV) and 16799 neutrons will likely escape the target. Figure in black on the left is the total energy spectrum of neutrons created in reaction . Figure in blue on the right is the neutron energy spectrum with energy cut applied.So, if we apply the energy cut in neutron spectrum which is a sum of neutrons coming from
and reactions at (0MeV)<E<=5MeV, then the ratio of unpolarized photons from and polarized photons from will be . In the same time we will loose of the "good" neutrons produced in reaction.I will verify if those spectra and all the ratios are the same in the case where we use the geometrical constrains applied by the detectors placement.