Difference between revisions of "Lab 9 RS"
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= Differentiating Circuit with clipping= | = Differentiating Circuit with clipping= | ||
− | + | 1) Construct the circuit below. | |
[[File:TF_EIM_Lab9a.png | 400 px]] | [[File:TF_EIM_Lab9a.png | 400 px]] | ||
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+ | 2) Select <math>R_1</math> and <math>R_2</math> such that the current from the +5V DC source is less than 1.0 mA and the DC voltage at <math>V_{out}</math> is 3 V when there is no input pulse. | ||
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− | + | 3) Select a capacitor <math>(C)</math> and a pulse width <math>\tau</math> to form a differentiating circuit for the pulse from the signal generator. Hint: <math>R_{12}C \ll \tau</math>. | |
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− | + | 4) plot <math>V_{in}</math> and <math>V_{out}</math> as a function of time using your scope observations. (20 pnts) | |
− | + | 5) Now add the diode circuit from part 1 to prevent <math>V_{out}</math> from rising above +5 V. Sketch the new circuit below. | |
− | + | 6) plot <math>V_{in}</math> and <math>V_{out}</math> as a function of time with the diode circuit you added using your scope observations. (the diode should clip off positive spikes) (20 pnts) | |
=Questions= | =Questions= |
Revision as of 05:41, 22 February 2011
Lab 9: Diode Circuits
Clipping Circuit
1.) Construct the circuit shown below using a silicon diode.
2.) Use a sine wave generator to drive the circuit so
where V and = 1kHz. (20 pnts)3.)Based on your observations using a oscilloscope, sketch the voltages
and as a function of time.4.)Do another sketch for
= 1.0 V and another for 10.0 V (DONT LET ANY SMOKE OUT!). (20 pnts)Differentiating Circuit with clipping
1) Construct the circuit below.
2) Select
and such that the current from the +5V DC source is less than 1.0 mA and the DC voltage at is 3 V when there is no input pulse.
Because we want to keep the current below and using . Solving this inequality we get the first condition for and
Also because we want and using . Solving this equation we get the second condition and
I am going to useand which satisfy both conditions above
3) Select a capacitor and a pulse width to form a differentiating circuit for the pulse from the signal generator. Hint: .
Taking and .
And choosing the the pulse width
I will be able to make good differentiator circuit.
4) plot
and as a function of time using your scope observations. (20 pnts)
5) Now add the diode circuit from part 1 to prevent from rising above +5 V. Sketch the new circuit below.
6) plot and as a function of time with the diode circuit you added using your scope observations. (the diode should clip off positive spikes) (20 pnts)
Questions
- Explain your results in parts 1 & 2 in terms of the diode turn-on voltage. (20 pnts)
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