Difference between revisions of "TF EIMLab6 Writeup"

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| [[File:TF_EIM_L6_RC10t.png|200px]]||[[File:TF_EIM_L6RCt.png| 200px]] || [[File:TF_EIM_L6RC0.1t.png|200px]]
 
| [[File:TF_EIM_L6_RC10t.png|200px]]||[[File:TF_EIM_L6RCt.png| 200px]] || [[File:TF_EIM_L6RC0.1t.png|200px]]
 
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|<math>R_1 C_1 =\tau/10 = 14.6 \mu s|| <math>R_1 C_1 =\tau = 146 \mu s</math> || <math>R_1 C_1 =10 \tau = 1.460</math>ms </math>
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|<math>R_1 C_1 =\tau/10 = 14.6 \mu s</math>|| <math>R_1 C_1 =\tau = 146 \mu s</math> || <math>R_1 C_1 =10 \tau = 1.460</math>ms  
 
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Revision as of 23:37, 8 February 2011

Lab 6 Pulses and RC Filters

Differentiator

1.) Adjust the pulse generator to output square pulses which at τ sec in time.

Possible capacitors

C1=1×106F
C2=10.24×109F

Possible Resistors

R1=1×103Ω
R2=14.35×103Ω


R1C1=τ1=(1×103Ω)(1×106F)=0.001 s
R1C1=τ2=(14.35×103Ω)(10.24×109F)=1.46×104
ω1=100rad/secν1=100/2π=16Hz
ω2=6805rad/secν2=1083Hz

tek012

R1C1=10τ2=1460μs


TF EIM L6 RC10t.png TF EIM L6RCt.png TF EIM L6RC0.1t.png
R1C1=τ/10=14.6μs R1C1=τ=146μs R1C1=10τ=1.460ms


2.)Construct the circuit below selecting an RC combination such that RC 1/10

TF EIM Lab6b.png

3.)MeasureVin and Vout. Sketch a picture comparingVout and Vin.

4.) Change the pulse width such that RC=τ

5.)MeasureVin and Vout.Sketch a picture comparingVout and Vin.

6.) Change the pulse width such thatRC=10τ

7.)Measure VinandVout.Sketch a picture comparingVout and Vin.


Questions

1.) What happens if than amplitude of Vin is doubled.

2.) What happens if R is doubled and C is halved?

Integrator

To illustrate the integrator circuit we need to have an input pulse which looks like the output of the above differentiator circuit. In other words, input a pulse whose output is obviously the integral of the input pulse.

TF EIM Lab6a.png


Forest_Electronic_Instrumentation_and_Measurement