Minimum accelerator energy to run experiment: Difference between revisions

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Created page with '[http://wiki.iac.isu.edu/index.php/PhotoFission_with_Polarized_Photons_from_HRRL Go Back] =Minimum accelerator energy to run experiment= ==condition 1: fitting the collimator s...'
 
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[http://wiki.iac.isu.edu/index.php/PhotoFission_with_Polarized_Photons_from_HRRL Go Back]
[http://wiki.iac.isu.edu/index.php/PhotoFission_with_Polarized_Photons_from_HRRL Go Back]


=Minimum accelerator energy to run experiment=
=condition 1: fitting the collimator size into the hole=
 
==condition 1: fitting the collimator size into the hole==
 
[[File:min_energy.png|800px]]
 
The minimum energy of accelerator (MeV) is limited by fitting the collimator size <math>r_2</math> into the hole R = 8.73 cm:
 
<math>x_2 + r_2 = R</math>
 
1) Assuming the collimator diameter is <math>\Theta_C</math>:
 
<math>\frac{1}{\sqrt{2}}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) +
      \frac{1}{2}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 33.1\ MeV  </math>
 
2) Assuming the collimator diameter is <math>\Theta_C/2</math>:
 
<math>\frac{1}{\sqrt{2}}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) +
      \frac{1}{2}\ (286+183)\ \tan\left(\frac{1}{2}\ \frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 26.3\ MeV  </math>
 
3) Assuming the collimator diameter is <math>\Theta_C/4</math>:
 
<math>\frac{1}{\sqrt{2}}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) +
      \frac{1}{2}\ (286+183)\ \tan\left(\frac{1}{4}\ \frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 22.8\ MeV  </math>
 
4) for arbitrary collimator size <math>\Theta_C/2</math>:
 
[[File:plot_energy_collimatorsize.jpeg]]
 
All energy above this line is good to run experiment
 
==condition 2: F1A = 286 cm==
 
1) assuming the collimator diameter is <math>\Theta_C</math>
 
<math> E_{min} = 73.7\ MeV  </math>
 
2) assuming the collimator diameter is <math>\Theta_C/2</math>
 
<math> E_{min} = 36.9\ MeV  </math>
 
3) assuming the collimator diameter is <math>\Theta_C/4</math>
 
<math> E_{min} = 18.4\ MeV  </math>
 
4) for arbitrary collimator size <math>\Theta_C/m</math>:
 
[[File:plot_energy_F1A.jpeg]]
 
All energy above this line is good to run experiment
 
==both conditions above are together==
 
[[File:plot_energy_bothcondition.jpeg]]
 
All energy above this lines is good to run experiment
 
[http://wiki.iac.isu.edu/index.php/PhotoFission_with_Polarized_Photons_from_HRRL Go Back]
 
=Minimum accelerator energy to run experiment=
 
==condition 1: fitting the collimator size into the hole==


[[File:min_energy.png|800px]]
[[File:min_energy.png|800px]]
Line 91: Line 30:
All energy above this line is good to run experiment
All energy above this line is good to run experiment


==condition 2: F1A = 286 cm==
=condition 2: F1A = 286 cm=


1) assuming the collimator diameter is <math>\Theta_C</math>
1) assuming the collimator diameter is <math>\Theta_C</math>
Line 111: Line 50:
All energy above this line is good to run experiment
All energy above this line is good to run experiment


==both conditions above are together==
=both conditions above are together=


[[File:plot_energy_bothcondition.jpeg]]
[[File:plot_energy_bothcondition.jpeg]]

Revision as of 19:03, 14 June 2010

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condition 1: fitting the collimator size into the hole

The minimum energy of accelerator (MeV) is limited by fitting the collimator size [math]\displaystyle{ r_2 }[/math] into the hole R = 8.73 cm:

[math]\displaystyle{ x_2 + r_2 = R }[/math]

1) Assuming the collimator diameter is [math]\displaystyle{ \Theta_C }[/math]: 

[math]\displaystyle{ \frac{1}{\sqrt{2}}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) +
       \frac{1}{2}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 33.1\ MeV   }[/math]

2) Assuming the collimator diameter is [math]\displaystyle{ \Theta_C/2 }[/math]: 

[math]\displaystyle{ \frac{1}{\sqrt{2}}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) +
       \frac{1}{2}\ (286+183)\ \tan\left(\frac{1}{2}\ \frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 26.3\ MeV   }[/math]

3) Assuming the collimator diameter is [math]\displaystyle{ \Theta_C/4 }[/math]: 

[math]\displaystyle{ \frac{1}{\sqrt{2}}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) +
       \frac{1}{2}\ (286+183)\ \tan\left(\frac{1}{4}\ \frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 22.8\ MeV   }[/math]

4) for arbitrary collimator size [math]\displaystyle{ \Theta_C/2 }[/math]:

All energy above this line is good to run experiment

condition 2: F1A = 286 cm

1) assuming the collimator diameter is [math]\displaystyle{ \Theta_C }[/math] 

[math]\displaystyle{  E_{min} = 73.7\ MeV   }[/math]

2) assuming the collimator diameter is [math]\displaystyle{ \Theta_C/2 }[/math] 

[math]\displaystyle{  E_{min} = 36.9\ MeV   }[/math]

3) assuming the collimator diameter is [math]\displaystyle{ \Theta_C/4 }[/math] 

[math]\displaystyle{  E_{min} = 18.4\ MeV   }[/math]

4) for arbitrary collimator size [math]\displaystyle{ \Theta_C/m }[/math]:

All energy above this line is good to run experiment

both conditions above are together

All energy above this lines is good to run experiment


Go Back

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