Megan Homework: Difference between revisions

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===Simplify===
===Simplify===


1.) <math>\frac{\sqrt{x}+4}{3-\sqrt{3}}</math>
1.) <math>\frac{\sqrt{x}+4}{3-\sqrt{x}}</math>


2.) <math>\frac{x^2}{\sqrt{x}+5}</math>
2.) <math>\frac{x^2}{\sqrt{x}+5}</math>

Revision as of 00:17, 13 April 2010

True/False

  1. [math]\displaystyle{ \sqrt{a} + \sqrt{a} = \sqrt{a+a} }[/math]
  2. [math]\displaystyle{ \sqrt{8x} = 2 \sqrt{4x} }[/math]
  3. [math]\displaystyle{ e^{-1/2} = -\sqrt{e} }[/math]
  4. [math]\displaystyle{ x^{-2/3} = \sqrt{x^3} }[/math]
  5. [math]\displaystyle{ (g \cdot f)(x) = g(x)f(x) }[/math]
  6. [math]\displaystyle{ (g \circ f)(x) = f(g(x)) }[/math]
  7. if [math]\displaystyle{ f(x) = 4x }[/math] and [math]\displaystyle{ g(x) = \sqrt{x} }[/math]
    1. [math]\displaystyle{ (g \circ f)(x) = 4 \sqrt{x} }[/math]
    2. [math]\displaystyle{ (g \circ g)(y) = \sqrt[4]{y} }[/math]
    3. [math]\displaystyle{ (g \circ f)(z) = (f \circ g)(z) }[/math]
  8. [math]\displaystyle{ t^2t^3 = t^6 }[/math]
  9. [math]\displaystyle{ \frac{2x+1}{x+1} = \frac{2x}{x} = 2 }[/math]

Simplify

  1. [math]\displaystyle{ \frac{2}{2+3\sqrt{2x}} }[/math]
  2. [math]\displaystyle{ \frac{x}{x^{-2/3}} }[/math]
  3. [math]\displaystyle{ r^{-1} }[/math]
  4. [math]\displaystyle{ \frac{x+1}{x^2-1} }[/math]

At what points are the following expressions undefined?

  1. [math]\displaystyle{ \frac{x-1}{x+1} }[/math]
  2. [math]\displaystyle{ x^{-1/2} }[/math]
  3. [math]\displaystyle{ \frac{6}{x^2-1} }[/math]
  4. [math]\displaystyle{ \frac{2}{|x+1|-1} }[/math]


Simplify

1.) [math]\displaystyle{ \frac{\sqrt{x}+4}{3-\sqrt{x}} }[/math]

2.) [math]\displaystyle{ \frac{x^2}{\sqrt{x}+5} }[/math]