Plastic Scintillator Calculation: Difference between revisions
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Probability of interaction <math>= \sigma_w * K </math> | Probability of interaction <math>= \sigma_w * K </math> | ||
For carbon <math>\sigma_{ | For carbon <math>\sigma_{nucleus} = 9.645*10^{-2} barns</math> or <math>9.645*10^{-26}cm^2</math> | ||
For hydrogen <math>\sigma_{elec} = </math> | For carbon <math>\sigma_{elec} = 1.030*10^{-2} barns</math> or <math>1.030*10^{-26}cm^2</math> | ||
For hydrogen <math>\sigma_{nucleus} = 2.688*10^{-3} barns</math> or <math>2.688*10^{-27}cm^2</math> | |||
For hydrogen <math>\sigma_{elec} = 1.716*10^{-3} barns</math> or <math>1.716*10^{-27}cm^2</math> | |||
[http://wiki.iac.isu.edu/index.php/PhotoFission_with_Polarized_Photons_from_HRRL Go Back] | [http://wiki.iac.isu.edu/index.php/PhotoFission_with_Polarized_Photons_from_HRRL Go Back] | ||
Revision as of 23:54, 4 February 2009
Below is the calculations done to determine the probability of pair production depending on thickness of the scintillator.
Molecules per [math]\displaystyle{ cm^3 = \frac{grams CH_{2}}{cm^3} * \frac{mol}{gram} * \frac{N[A]}{mol} }[/math]
Molecules per [math]\displaystyle{ cm^2 (K) = \frac{Molecules}{cm^3} * Thickness }[/math]
Weighted cross-section [math]\displaystyle{ (\sigma_w) = (\sigma_{elec}C + \sigma_{nucleus}C) + 2(\sigma_{elec}H + \sigma_{nucleus}H) }[/math]
Probability of interaction [math]\displaystyle{ = \sigma_w * K }[/math]
For carbon [math]\displaystyle{ \sigma_{nucleus} = 9.645*10^{-2} barns }[/math] or [math]\displaystyle{ 9.645*10^{-26}cm^2 }[/math]
For carbon [math]\displaystyle{ \sigma_{elec} = 1.030*10^{-2} barns }[/math] or [math]\displaystyle{ 1.030*10^{-26}cm^2 }[/math]
For hydrogen [math]\displaystyle{ \sigma_{nucleus} = 2.688*10^{-3} barns }[/math] or [math]\displaystyle{ 2.688*10^{-27}cm^2 }[/math]
For hydrogen [math]\displaystyle{ \sigma_{elec} = 1.716*10^{-3} barns }[/math] or [math]\displaystyle{ 1.716*10^{-27}cm^2 }[/math]