Conversion TDC to Energy

Method 1:

Calculation

When electron beam hit the radiator, TDC start to count. It will take gamma 14 ns to reach the target. Then after some time $t_{n1}$, neutron arrive to the detectors.

Let's call the the total time from electron beam hit the radiator to neutron to be detected is $t_n$. So,

$t_n = t_{n1} + 14 = \frac{d}{v} + 14 ns$

where d is the distance between detector and target, v is speed of neutron. So,

$v=\frac{d}{(t-14)*10^{-9}} m/s$

where should be in the unit of nano second.

$\beta_n=\frac{v}{c}$

$\gamma_n=\sqrt{\frac{1}{1-\beta^2}}$

$E_{tot}=M_n\gamma_nc^2$

$E_k=E_{tot}-M_n c^2$

Data

For data go to link:

http://inca.iac.isu.edu/~setiniyaz/photofis/Method1/

or click on:

File:Method 1 polarized.pdf

File:Method 1 unpolarized top.pdf

File:Method 1 unpolarized side.pdf

Method 2: Using time difference in two peaks

Calculation

If we assume gamma flash is coming from target, then by time difference in gamma peak and neutron peak, we can tell the energies in neutrons.

$t_n$: Neutron time of flight

$t_{\gamma}$: Gamma time of flight

d: Distance between detector and target.

d for polarized case: $d_{pol}$ = 91.25 inches = 231.775 cm.

d for unpolarized top detector: $d_{unpol top}$=96.25 inches = 244.745 cm.

d for unpolarized side detector: $d_{unpol side}$=91.39 inches = 232.131 cm.

$t_n-t_{\gamma}=\frac{d}{v}-\frac{d}{c}=d(\frac{1}{v}-\frac{1}{c}$)

=> $v=\frac{1}{\frac{t_n-t_{\gamma}}{d}-\frac{1}{c}}$

$\beta_n=\frac{v}{c}$

$\gamma_n=\sqrt{\frac{1}{1-\beta^2}}$

$E_{tot}=M_n\gamma_nc^2$

$E_k=E_{tot}-M_n c^2$

Data

For data go to Link below:

http://inca.iac.isu.edu/~setiniyaz/photofis/TDCtoMeV/

or click on:

File:Method 2 polarized.pdf

File:Method 2 unpolarized top.pdf

File:Method 2 unpolarized side.pdf

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