Notes from July 2nd, 2008 Meeting: Difference between revisions

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target thickness in <math>\frac{Dnuclei}{cm^{2}} \times \sigma in cm^{2}</math>
target thickness in <math>\frac{Dnuclei}{cm^{2}} \times \sigma in cm^{2}</math>
==Worst Case Isotropic Neutrons==
Let's say we have:
radius detector = 1 cm
1 meter away
fractional solid angle = <math>\frac{\pi * (1 cm)^{2}}{4 \pi (100cm^{2}} = \frac{1}{4} \times 10^{-4}</math> <= geometrical acceptance
10 \degree efficient of n \degree detection
<math> 10^{4} \frac{photodisintegrations}{sec} \times \frac{1}{4} \cdot 10^{-4} \times 10^{-1} = .025 \frac{events}{sec}</math>
                                  ^          ^
                                  |          |
                                geometry  efficiency
time for 10,sup>4</sup> events = 100 hours for 1%
                                  24 hours for 2%
                                  6 hours for 4%
Therefore, this experiment is do able.

Revision as of 13:40, 3 July 2008

Numbers for rate of Brems intensity spectrum:

[math]\displaystyle{ \frac{e^{-}}{sec} }[/math] = [math]\displaystyle{ 30 \cdot 10^{-3} \frac{Coulomb}{sec} \times \frac{50 \cdot 10^{-9} sec}{10^{-3} sec} \times \frac{1 \cdot e^{-}}{1.6 \cdot 10^{-19}Coulomb} => 9.4 \cdot 10^{12} \frac{e^{-}}{sec} }[/math]

[math]\displaystyle{ 10^{-3} \frac{\frac{\gamma 's}{MeV}}{\frac{e^{-}}{radiation lengths}} \times 2 \cdot 10^{-4} radiation lengths \times 15 MeV \times 9.4 \cdot 10^{12} \frac{e^{-}}{sec}=2.8 \cdot 10^{7} \frac{\gamma}{sec} }[/math]

Number of ɣ + d -> n + p events/sec

[math]\displaystyle{ 2.8 \cdot 10^{7} \frac{\gamma}{sec} \times 4 \cdot 10^{-4} = 10^{4} }[/math]

Probability of Photodisintegration Event

target thickness in [math]\displaystyle{ \frac{Dnuclei}{cm^{2}} \times \sigma in cm^{2} }[/math]

Worst Case Isotropic Neutrons

Let's say we have:

radius detector = 1 cm

1 meter away

fractional solid angle = [math]\displaystyle{ \frac{\pi * (1 cm)^{2}}{4 \pi (100cm^{2}} = \frac{1}{4} \times 10^{-4} }[/math] <= geometrical acceptance

10 \degree efficient of n \degree detection [math]\displaystyle{ 10^{4} \frac{photodisintegrations}{sec} \times \frac{1}{4} \cdot 10^{-4} \times 10^{-1} = .025 \frac{events}{sec} }[/math]

                                 ^           ^
                                 |           |
                               geometry  efficiency


time for 10,sup>4 events = 100 hours for 1%

                                 24 hours for 2%
                                  6 hours for 4%

Therefore, this experiment is do able.