Difference between revisions of "Thickness of Lead to block photons"

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<math>\frac{h _2}{84.56 + d} = tan(1.95 + .25 \cdot 1.95) => h _2 = .042568d + 3.599557</math>
 
<math>\frac{h _2}{84.56 + d} = tan(1.95 + .25 \cdot 1.95) => h _2 = .042568d + 3.599557</math>
  
<math>tan \theta = \frac{h _1}{4.56 cm} => 25.6^{\circ}</math>
+
<math>tan \theta = \frac{2.1589 cm}{4.56 cm} => 25.6^{\circ}</math>
  
 
<math>tan \theta = \frac{h _2}{4.56 cm + d} => tan (25.6^{\circ}) =\frac{.042568d + 3.599557}{d + 4.56 cm}</math>
 
<math>tan \theta = \frac{h _2}{4.56 cm + d} => tan (25.6^{\circ}) =\frac{.042568d + 3.599557}{d + 4.56 cm}</math>
  
 
∴ <math>\textbf{the}</math> <math>\textbf{thickness}</math> <math>\textbf{of}</math> <math>\textbf{the}</math> <math>\textbf{lead = 3.24 cm}</math>
 
∴ <math>\textbf{the}</math> <math>\textbf{thickness}</math> <math>\textbf{of}</math> <math>\textbf{the}</math> <math>\textbf{lead = 3.24 cm}</math>

Revision as of 13:11, 5 June 2008

[math]\frac{h _1}{84.56 cm} = tan(1.95 \times .25 \cdot 1.95) =\gt h _1 = 2.1589 cm[/math]

[math]\frac{h _2}{84.56 + d} = tan(1.95 + .25 \cdot 1.95) =\gt h _2 = .042568d + 3.599557[/math]

[math]tan \theta = \frac{2.1589 cm}{4.56 cm} =\gt 25.6^{\circ}[/math]

[math]tan \theta = \frac{h _2}{4.56 cm + d} =\gt tan (25.6^{\circ}) =\frac{.042568d + 3.599557}{d + 4.56 cm}[/math]

[math]\textbf{the}[/math] [math]\textbf{thickness}[/math] [math]\textbf{of}[/math] [math]\textbf{the}[/math] [math]\textbf{lead = 3.24 cm}[/math]