Difference between revisions of "Radiators Temperature"
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To find energy deposited by each electron, we need to use formula | To find energy deposited by each electron, we need to use formula | ||
− | <math> E_{dep one}=(dE/dx)_{coll}*t </math> | + | <math> E_{dep one}=(dE/dx)_{coll}*t </math> |
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|}<br> | |}<br> | ||
− | Table of | + | Table of energy calculations for the thickness of 0.001 Radiation Length of radiators , <math>(dE/dx)_{coll}</math> (from National Institute of Standards and Technology. Link: [[http://physics.nist.gov/PhysRefData/Star/Text/ESTAR.html]]) and energy calculations |
{| border="1" cellpadding="20" cellspacing="0" | {| border="1" cellpadding="20" cellspacing="0" | ||
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|t(<math>gcm^{-2}</math>) | |t(<math>gcm^{-2}</math>) | ||
|- | |- | ||
− | |Al ||1.676 | + | |Al ||1.676 || |
|- | |- | ||
− | |W ||1.247 | + | |W ||1.247 || |
|- | |- | ||
− | |Ti ||1.555 | + | |Ti ||1.555 || |
|- | |- | ||
− | |Fe ||1.529 | + | |Fe ||1.529 || |
Revision as of 16:31, 1 June 2008
Calculation of Equilibrium temperature of Radiators
1.Calculating number of particles per second
We have electron beam of:
Frequency: f=1000Hz
Peak current: I=10mAmp=0.01 Amp
Pulse width: ∆t= 50 ns=5*10-8 seconds
So, how many electrons we have in each second?
By Q=It, we have
N*e=f*I*∆t
Where Ne is the total electron numbers hits target per second, e is electron charge and f, I and ∆t are given above. So
N= f*I*∆t/e=1000*0.01*5*10-8/(1.6*10-19)=3.12075*1012
So, we have around 3.12075*1012 electrons hit radiator per second.
2.Calculating Energy deposited per second
If we find the energy deposited by each electron and multiply to the total number of electrons in each second, we will find the total energy per second deposited in radiator.
To find energy deposited by each electron, we need to use formula
Where is is energy deposited by one electron, is mean energy loss (also stopping power) by collision of electron and t is thickness of the radiator.
Actually, energy loss of electron comes from two parts: the emission of electromagnetic radiation arising from scattering in the electric field of a nucleus (bremsstrahlung) and collisional energy loss when passing through matter. But bremsstrahlung will not contribute to the temperature, since it is radiation.
Stopping power can be found from nuclear data tables
and thickness is 0.001 times of radiation length. From Particle Data group we got radiation length and average total stopping powers around 15MeV for electrons in these materials from National Institute of Standards and TechnologyTable of Radiation Lengths ( From Particle Data group. Link: [1]).
Elements | Radiation Lengths |
Al | 24.01 |
W | 6.76 |
Ti | 16.16 |
Fe | 13.84 |
Table of energy calculations for the thickness of 0.001 Radiation Length of radiators , [2]]) and energy calculations
(from National Institute of Standards and Technology. Link: [Elements | t( | )|
Al | 1.676 | |
W | 1.247 | |
Ti | 1.555 | |
Fe | 1.529 |