Photon yield: Difference between revisions

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[[Image:Ta_yield.png|500px]]
[[Image:Ta_yield.png|500px]]
''Figure 2:'' Photon yield from Ta target of thickness 4.16 g/<math>cm^2</math> in the range of angles <math>0^0 < \theta < 2^0 </math> and for <math>E_{\gamma} > 6 MeV</math>.

Revision as of 17:25, 24 April 2008

There were used couple of targets to simulate bremsstrahlung radiation yield. Energy of incident electrons was chosen to be E = 14.0 MeV. Number of incident electrons was [math]\displaystyle{ 10^4 }[/math]. The radiatoin yield was estimated for [math]\displaystyle{ E_{\gamma} > 6 MeV }[/math] in the range of angles [math]\displaystyle{ 0^0 < \theta < 2^0 }[/math], [math]\displaystyle{ \theta }[/math] is opening angle of the radiation cone.

Tantalum target

The maximum photon yield for Ta was 30[math]\displaystyle{ \gamma }[/math] per [math]\displaystyle{ 10^4 }[/math] incident electrons.

Figure 1: Energy specrtum of photons coming out from Ta target of thickness 4.16 g/[math]\displaystyle{ cm^2 }[/math].

Figure 2: Photon yield from Ta target of thickness 4.16 g/[math]\displaystyle{ cm^2 }[/math] in the range of angles [math]\displaystyle{ 0^0 < \theta < 2^0 }[/math] and for [math]\displaystyle{ E_{\gamma} > 6 MeV }[/math].