Difference between revisions of "Spontaneous fission rate for sample of U-235 (1mg/cm^2)"
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− | Goal: Calculate the fission rate of | + | Goal: Calculate the fission rate of the bomb grade <math>U^{235}</math> that has a mass of <math>.91*10^{-3}</math> |
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Procedure: | Procedure: | ||
+ | Givens- <math> T_{1/2} = 7.038*10^{8} year \times 3.1536*10^{7} sec = 2.2195*10^{16} sec</math> | ||
− | + | <math> m = .91 \times 10^{-3} g</math> | |
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− | <math> | ||
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+ | Procedure- <math>\lambda = \frac{\ln{2}}{T_{1/2}} = \frac{\ln{2}}{2.2195*10^{16} sec} = 3.12*10^{-17} sec^{-1}</math> | ||
− | + | <math>N = \frac{N_a}{A} m = \frac{6.022*10^{23} \frac{nuclei}{mol}}{235 \frac{g}{mol}} .91 * 10^{-3} g = 2.33*10^{18} nuclei</math> | |
− | <math>\ | + | <math>R = \lambda N = 3.12*10^{-17} sec^{-1} \times 2.33*10^{18} nuclei = \textbf{72.696 nuclei}</math> |
Revision as of 15:59, 24 April 2008
Goal: Calculate the fission rate of the bomb grade
that has a mass of Procedure: Givens-
Procedure-