TF InclusiveDeltaDoverD: Difference between revisions
No edit summary |
No edit summary |
||
| Line 11: | Line 11: | ||
using the above definition to define the proton and neutron unpolarized structure function: | using the above definition to define the proton and neutron unpolarized structure function : | ||
<math> F_1^p(x) \equiv \frac{1}{2} \sum_q e_i^2 q_i^p(x) = \frac{1}{2}\left [ \left( \frac{2}{3} \right)^2 u^p(x)+ \left( \frac{-1}{3} \right)^2 d^p(x)\right ] =\frac{1}{2} \left [\frac{4}{9}u^p(x) + \frac{1}{9}d^p(x)\right ]</math> | <math> F_1^p(x) \equiv \frac{1}{2} \sum_q e_i^2 q_i^p(x) = \frac{1}{2}\left [ \left( \frac{2}{3} \right)^2 u^p(x)+ \left( \frac{-1}{3} \right)^2 d^p(x)\right ] =\frac{1}{2} \left [\frac{4}{9}u^p(x) + \frac{1}{9}d^p(x)\right ]</math> | ||
| Line 17: | Line 17: | ||
<math> F_1^n(x) \equiv \frac{1}{2} \sum_q e_i^2 q_i^p(x) = \frac{1}{2}\left [ \left( \frac{2}{3} \right)^2 u^n(x)+ \left( \frac{-1}{3} \right)^2 d^n(x)\right ] =\frac{1}{2} \left [\frac{4}{9}u^n(x) + \frac{1}{9}d^n(x)\right ]</math> | <math> F_1^n(x) \equiv \frac{1}{2} \sum_q e_i^2 q_i^p(x) = \frac{1}{2}\left [ \left( \frac{2}{3} \right)^2 u^n(x)+ \left( \frac{-1}{3} \right)^2 d^n(x)\right ] =\frac{1}{2} \left [\frac{4}{9}u^n(x) + \frac{1}{9}d^n(x)\right ]</math> | ||
;The above is true within the framework of the constituent quark model when in the valence quark region <math>\left ( x_bj>0.5 \right )</math> where the more massive quarks are ignored as well as anti-quarks | |||
Using Isospin symmetry | Using Isospin symmetry | ||
| Line 26: | Line 28: | ||
<math> F_1^p(x) =\frac{1}{2} \left [\frac{4}{9}u(x) + \frac{1}{9}d(x)\right ] \;\;\;\;\;</math> <math> F_1^n(x)=\frac{1}{2} \left [\frac{4}{9}d(x) + \frac{1}{9}u(x)\right ]</math> | <math> F_1^p(x) =\frac{1}{2} \left [\frac{4}{9}u(x) + \frac{1}{9}d(x)\right ] \;\;\;\;\;</math> <math> F_1^n(x)=\frac{1}{2} \left [\frac{4}{9}d(x) + \frac{1}{9}u(x)\right ]</math> | ||
similarly for the polarized structure function | |||
<math> g_1(x) \equiv \frac{1}{2} \sum_q e_i^2 \Delta q_i(x) </math> | |||
<math>g_1^d \approx \left ( 1 - 1.5 \omega_D \right ) \left ( g_1^n + g_1^p \right )</math><ref> Eq. 28 from https://arxiv.org/abs/1505.07877 which is based on https://arxiv.org/abs/0809.4308</ref> | <math>g_1^d \approx \left ( 1 - 1.5 \omega_D \right ) \left ( g_1^n + g_1^p \right )</math><ref> Eq. 28 from https://arxiv.org/abs/1505.07877 which is based on https://arxiv.org/abs/0809.4308</ref> | ||
Revision as of 16:16, 22 September 2018
[math]\displaystyle{ q_i(x) \equiv q_i^{\parallel}(x) + q_i^{\perp}(x) }[/math]
[math]\displaystyle{ \Delta q_i(x) \equiv q_i^{\parallel}(x) - q_i^{\perp}(x) }[/math]
[math]\displaystyle{ F_1(x) \equiv \frac{1}{2} \sum_q e_i^2 q_i(x) }[/math]
using the above definition to define the proton and neutron unpolarized structure function :
[math]\displaystyle{ F_1^p(x) \equiv \frac{1}{2} \sum_q e_i^2 q_i^p(x) = \frac{1}{2}\left [ \left( \frac{2}{3} \right)^2 u^p(x)+ \left( \frac{-1}{3} \right)^2 d^p(x)\right ] =\frac{1}{2} \left [\frac{4}{9}u^p(x) + \frac{1}{9}d^p(x)\right ] }[/math]
[math]\displaystyle{ F_1^n(x) \equiv \frac{1}{2} \sum_q e_i^2 q_i^p(x) = \frac{1}{2}\left [ \left( \frac{2}{3} \right)^2 u^n(x)+ \left( \frac{-1}{3} \right)^2 d^n(x)\right ] =\frac{1}{2} \left [\frac{4}{9}u^n(x) + \frac{1}{9}d^n(x)\right ] }[/math]
- The above is true within the framework of the constituent quark model when in the valence quark region [math]\displaystyle{ \left ( x_bj>0.5 \right ) }[/math] where the more massive quarks are ignored as well as anti-quarks
Using Isospin symmetry
[math]\displaystyle{ u(x) \equiv u^p(x)\equiv d^n(x) \;\;\;\;\; }[/math] and [math]\displaystyle{ \;\;\;\;\;d(x) \equiv d^p(x)\equiv u^n(x) }[/math]
The unpolarized structure functions for the proton and neutron may be written as
[math]\displaystyle{ F_1^p(x) =\frac{1}{2} \left [\frac{4}{9}u(x) + \frac{1}{9}d(x)\right ] \;\;\;\;\; }[/math] [math]\displaystyle{ F_1^n(x)=\frac{1}{2} \left [\frac{4}{9}d(x) + \frac{1}{9}u(x)\right ] }[/math]
similarly for the polarized structure function
[math]\displaystyle{ g_1(x) \equiv \frac{1}{2} \sum_q e_i^2 \Delta q_i(x) }[/math]
[math]\displaystyle{ g_1^d \approx \left ( 1 - 1.5 \omega_D \right ) \left ( g_1^n + g_1^p \right ) }[/math]<ref> Eq. 28 from https://arxiv.org/abs/1505.07877 which is based on https://arxiv.org/abs/0809.4308</ref>
<references />