Difference between revisions of "Differential Cross-Section"
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<center><math> \mathfrak{M}_{e^-e^-}= e^2\left ( \frac{\mathbf P_1 \mathbf P_2+\mathbf P_{1'} \mathbf P_{2'}+\mathbf P_{1'} \mathbf P_2+\mathbf P_1 \mathbf P_{2'}}{(\mathbf P_{2'}-\mathbf P_2)^2}- \frac{\mathbf P_1 \mathbf P_2+\mathbf P_{2'} \mathbf P_{1'}+\mathbf P_{2'} \mathbf P_2+\mathbf P_1 \mathbf P_{1'}}{(\mathbf P_{1'}-\mathbf P_2)^2} \right )</math></center> | <center><math> \mathfrak{M}_{e^-e^-}= e^2\left ( \frac{\mathbf P_1 \mathbf P_2+\mathbf P_{1'} \mathbf P_{2'}+\mathbf P_{1'} \mathbf P_2+\mathbf P_1 \mathbf P_{2'}}{(\mathbf P_{2'}-\mathbf P_2)^2}- \frac{\mathbf P_1 \mathbf P_2+\mathbf P_{2'} \mathbf P_{1'}+\mathbf P_{2'} \mathbf P_2+\mathbf P_1 \mathbf P_{1'}}{(\mathbf P_{1'}-\mathbf P_2)^2} \right )</math></center> | ||
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+ | <center><math> \mathfrak{M}_{e^-e^-}= e^2\left ( \frac{\mathbf P_1 \mathbf P_2+\mathbf P_{1'} \mathbf P_{2'}+\mathbf P_{1'} \mathbf P_2+\mathbf P_1 \mathbf P_{2'}}{t}- \frac{\mathbf P_1 \mathbf P_2+\mathbf P_{2'} \mathbf P_{1'}+\mathbf P_{2'} \mathbf P_2+\mathbf P_1 \mathbf P_{1'}}{u} \right )</math></center> | ||
<center><math>\mathfrak{M}_{e^-e^-}=e^2 \left (\frac{u-s}{t}+\frac{t-s}{u} \right )</math></center> | <center><math>\mathfrak{M}_{e^-e^-}=e^2 \left (\frac{u-s}{t}+\frac{t-s}{u} \right )</math></center> |
Revision as of 15:14, 24 June 2017