Difference between revisions of "Differential Cross-Section"

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<center><math>-i \mathfrak{M}_{e^-e^-}=-i \left ( \frac{e^2(\mathbf P_1+\mathbf P_{1'})_{\mu}(\mathbf P_2+\mathbf P_{2'})^{\mu}}{(\mathbf P_{2'}-\mathbf P_2)^2}- \frac{e^2(\mathbf P_1+\mathbf P_{2'})_{\mu}(\mathbf P_2+\mathbf P_{1'})^{\mu}}{(\mathbf P_{1'}-\mathbf P_2)^2} \right )</math></center>
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<center><math>-i \mathfrak{M}_{e^-e^-}=-i \left ( \frac{e^2(\mathbf p_1+\mathbf p_{1'})_{\mu}(\mathbf p_2+\mathbf p_{2'})^{\mu}}{(\mathbf p_{2'}-\mathbf p_2)^2}- \frac{e^2(\mathbf p_1+\mathbf p_{2'})_{\mu}(\mathbf p_2+\mathbf p_{1'})^{\mu}}{(\mathbf p_{1'}-\mathbf p_2)^2} \right )</math></center>
  
  

Revision as of 15:12, 24 June 2017

iMee=i(e2(p1+p1)μ(p2+p2)μ(p2p2)2e2(p1+p2)μ(p2+p1)μ(p1p2)2)


Mee=e2(P1P2+P1P2+P1P2+P1P2(P2P2)2P1P2+P2P1+P2P2+P1P1(P1P2)2)


Mee=e2(ust+tsu)