Difference between revisions of "Differential Cross-Section"
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<center><math>-i \mathfrak{M}_{e^-e^-}=-i \left ( \frac{e^2(p_A+p_C)_{\mu}(p_B+p_D)^{\mu}}{(p_D-p_B)^2}- \frac{e^2(p_A+p_D)_{\mu}(p_B+p_C)^{\mu}}{(p_C-p_B)^2} \right )</math></center> | <center><math>-i \mathfrak{M}_{e^-e^-}=-i \left ( \frac{e^2(p_A+p_C)_{\mu}(p_B+p_D)^{\mu}}{(p_D-p_B)^2}- \frac{e^2(p_A+p_D)_{\mu}(p_B+p_C)^{\mu}}{(p_C-p_B)^2} \right )</math></center> | ||
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| + | <center><math> \mathfrak{M}_{e^-e^-}= e^2\left ( \frac{(p_Ap_B+p_Cp_D+p_Cp_B+p_Ap_D}{(p_D-p_B)^2}- \frac{(p_Ap_B+p_Dp_C+p_Dp_B+p_Ap_C}{(p_C-p_B)^2} \right )</math></center> | ||
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<center><math>\mathfrak{M}_{e^-e^-}=e^2 \left (\frac{u-s}{t}+\frac{t-s}{u} \right )</math></center> | <center><math>\mathfrak{M}_{e^-e^-}=e^2 \left (\frac{u-s}{t}+\frac{t-s}{u} \right )</math></center> | ||
Revision as of 14:52, 24 June 2017