Difference between revisions of "Circular Cross Sections"

From New IAC Wiki
Jump to navigation Jump to search
(Created page with "==Circular Conic Section== If the conic is an circle, e=0. This implies <center><math>e=\frac{\sin (\beta)}{\sin (\alpha)}=\frac{\sin (25^{\circ})}{\sin (90-\theta)}=0</math><…")
 
Line 13: Line 13:
  
 
The sector angle will never be perpendicular to the plane of the light cone, so this is not a physical possibility.
 
The sector angle will never be perpendicular to the plane of the light cone, so this is not a physical possibility.
 +
 +
 +
=[[VanWasshenova_Thesis#DC_Super_Layer_1:Layer_1|<-Back]]=
 +
=[[Elliptical_Cross_Sections|Forward->]]=

Revision as of 04:27, 4 March 2017

Circular Conic Section

If the conic is an circle, e=0. This implies

[math]e=\frac{\sin (\beta)}{\sin (\alpha)}=\frac{\sin (25^{\circ})}{\sin (90-\theta)}=0[/math]


Using the relation

[math]sin(90^{\circ}-\theta)=cos(\theta)[/math]
[math]\frac{sin (25^{\circ})}{0}=cos( \theta) =\infty[/math]


The sector angle will never be perpendicular to the plane of the light cone, so this is not a physical possibility.


<-Back

Forward->

Retrieved from "https://wiki.iac.isu.edu/index.php?title=Circular_Cross_Sections&oldid=113114"