Determining wire-phi correspondance: Difference between revisions

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Following the rules of conic sections we know that the eccentricity of the conic is given by:
Following the rules of conic sections we know that the eccentricity of the conic is given by:


<center><math>e=\frac{\sin [\beta]}{\sin[\alpha]}</math></center>
<center><math>e=\frac{\sin \beta}{\sin\alpha}</math></center>





Revision as of 05:19, 3 January 2017


Using Mathematica, we can produce a 3D rendering of how the sectors for Level 1 would have to interact with a steady angle theta with respect to the beam line, as angle phi is rotated through 360 degrees.


Looking just at sector 1, we can see that the intersection of level 1 and the cone of constant angle theta forms a conic section.



Following the rules of conic sections we know that the eccentricity of the conic is given by:

[math]\displaystyle{ e=\frac{\sin \beta}{\sin\alpha} }[/math]


Where β is the angle of the plane, and α is the slant of the cone.

If the conic is an circle, e=0

If the conic is an parabola, e=1

If the conic is an ellipse, [math]\displaystyle{ e=\sqrt{1-\frac{b^2}{a^2}} }[/math]

File:Conic section.png.png