Difference between revisions of "DV RunGroupC Moller"
(→Step 1) |
(→Step 1) |
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| Line 17: | Line 17: | ||
[[File:ElectronMomentumLabFrame.jpg]][[File:MollerMomentumLabFrame.jpg]] | [[File:ElectronMomentumLabFrame.jpg]][[File:MollerMomentumLabFrame.jpg]] | ||
| − | In the collision of two particles of mass | + | In the collision of two particles of mass m<sub>1</sub> and m<sub>2</sub>, the total energy in the center of mass frame can be written |
''<center>E<sub>cm</sub>=[(E<sub>1</sub>+E<sub>2</sub>)<sup>2</sup>-(p<sub>1</sub>+p<sub>2</sub>)<sup>2</sup>]<sup>1/2</sup></center>'' | ''<center>E<sub>cm</sub>=[(E<sub>1</sub>+E<sub>2</sub>)<sup>2</sup>-(p<sub>1</sub>+p<sub>2</sub>)<sup>2</sup>]<sup>1/2</sup></center>'' | ||
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'''[[Comparing experimental vs. theoretical for Møller differential cross section]]''' 11GeV | '''[[Comparing experimental vs. theoretical for Møller differential cross section]]''' 11GeV | ||
| + | |||
| + | Converting the number of electrons to nano-barns, | ||
| + | |||
| + | <math>L= \left( | ||
| + | \frac{\left(70.85 kg\right) \times \left(1 mole\right) \times \left(1000 g\right) \times \left(6E23 atoms\right) \times \left(1 cm\right) \times \left(1 m\right) \times \left(1E-28 m^2\right)}{\left(1 m\right) \times \left(2.02 g\right) \times \left(1 kg\right) \times \left(1 mole\right) \times \left(100 cm\right) \times \left(1 barn\right)} | ||
| + | \right)</math> | ||
[[File:FinalThetaCM.jpg]][[File:V3.jpg]] | [[File:FinalThetaCM.jpg]][[File:V3.jpg]] | ||
Revision as of 04:26, 24 April 2015
Simulating the Moller scattering background for EG1
Step 1
Determine the Moller background using an LH2 target to check the physics in GEANT4
Incident electron energy varies from 1-11 GeV.
LH2 target is a cylinder with a 1.5 cm diameter and 1 cm thickness.
(Following dimensions listed on page 8 of File:PHY02-33.pdf)
Numbers Moller electrons per incident electron.
While 2nd and 3rd generations are created, only 2 2nd generation daughter particles are created for 1E6 incident particles. All knock on electrons are not counted.
Momentum and angular distributions. 11GeV
In the collision of two particles of mass m1 and m2, the total energy in the center of mass frame can be written
where θ is the angle between the particles. In the frame where one particle (m2) is at rest
The velocity of the center of mass in the lab frame is
where plab≡p1 lab and
This gives the momenta of the particles in the center of mass to have equal magnitude, but opposite directions
For an incoming electron with momentum of 11GeV, we should find the momentum in the center of mass to be around 50 MeV which is confirmed in the the plots.
Comparing experimental vs. theoretical for Møller differential cross section 11GeV
Converting the number of electrons to nano-barns,
Step 2
Replace the LH2 target with an NH3 target and compare with LH2 target.
Step 3
Determine impact of Solenoid magnet on Moller events
Papers used
A polarized target for the CLAS detectorFile:PHY02-33.pdf
An investigation of the spin structure of the proton in deep inelastic scattering of polarized muons on polarized protons File:1819.pdf