Difference between revisions of "HRRL Pos Test 27Jul2012 Data Ana 1 MeV"

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|run in||run out || NaI Left: in sub out || NaI Right: in sub out|| NaI Left: overlap in and out || NaI Right: overlap in and out ||e- rate (Hz)||e+ rate (Hz)||e+/e+ ratop || e- current (A)
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{| border="1"  |cellpadding="20" cellspacing="0
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|  run#  || Positron Energy ||T1 || Sweeping Magnet || Positron to Electron Ratio
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|  3727  ||  1 MeV  || in || in ||<math>{R}_{1MeV,in,1} = ( 3.7 \pm 3.9 )\times 10^{-17} </math>
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|  3728  ||  1 MeV  || in || out ||<math>{R}_{1MeV,in,1} = ( 2.9 \pm 1.2 )\times 10^{-16} </math>
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|  3729  ||  1 MeV  || out || out ||<math>{R}_{1MeV,in,1} = ( 3.9 \pm 4.0 )\times 10^{-17} </math>
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|  3730  ||  1 MeV  || in || out ||<math>{R}_{1MeV,in,1} = ( 1.6 \pm 0.9 )\times 10^{-16} </math>
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|  3731  ||  1 MeV  || out || out ||<math>{R}_{1MeV,in,1} = ( 3.1 \pm 3.4 )\times 10^{-17} </math>
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|Average for T2 in||  1 MeV  ||  signal |||| <math>{\bar R}_{1MeV,sg} = ( 2.3 \pm 0.9 )\times 10^{-16} </math>
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|Average for T2 out||  1 MeV  ||background|| || <math>{\bar R}_{1MeV,bg} = ( 3.6 \pm 0.4 )\times 10^{-17} </math>
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|Average for in subtract out ||  1 MeV  ||  out || ||  <math>{R}_{1MeV} = ( 1.9 \pm 0.9 )\times 10^{-16} </math>
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Latest revision as of 00:06, 11 October 2012

run in run out NaI Left: in sub out NaI Right: in sub out NaI Left: overlap in and out NaI Right: overlap in and out e- rate (Hz) e+ rate (Hz) e+/e+ ratop e- current (A)
run# Positron Energy T1 Sweeping Magnet Positron to Electron Ratio
3727 1 MeV in in [math]{R}_{1MeV,in,1} = ( 3.7 \pm 3.9 )\times 10^{-17} [/math]
3728 1 MeV in out [math]{R}_{1MeV,in,1} = ( 2.9 \pm 1.2 )\times 10^{-16} [/math]
3729 1 MeV out out [math]{R}_{1MeV,in,1} = ( 3.9 \pm 4.0 )\times 10^{-17} [/math]
3730 1 MeV in out [math]{R}_{1MeV,in,1} = ( 1.6 \pm 0.9 )\times 10^{-16} [/math]
3731 1 MeV out out [math]{R}_{1MeV,in,1} = ( 3.1 \pm 3.4 )\times 10^{-17} [/math]
Average for T2 in 1 MeV signal [math]{\bar R}_{1MeV,sg} = ( 2.3 \pm 0.9 )\times 10^{-16} [/math]
Average for T2 out 1 MeV background [math]{\bar R}_{1MeV,bg} = ( 3.6 \pm 0.4 )\times 10^{-17} [/math]
Average for in subtract out 1 MeV out [math]{R}_{1MeV} = ( 1.9 \pm 0.9 )\times 10^{-16} [/math]







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